In a reaction substrate is available in a concentration that is l000times the Km value of the enzyme. After 9 minutes of reaction, l7o substrate is conveed to product (12 microgram/ml). If the concentration of the enzyme is changed to 1/3 and concentration of substrate is doubled. What is the time taken to conve the substrate into the same amount of product, i.e. I 2microgram/ml?
9 minutes
4.5 minutes
27 minutes
13.5 minutes
Ans: C. 27 minutesRef: Lehninger principles of biochemistry, 6t' ed., pg. 204During derivation of Michaelis-Menten equation,If total enzyme concentration is reduced by 1/3 and is very high then Vmax also become l/3.So in this question same amount of product will be fbrmed in 27 rninutes (3 x 9min)