"""
Largest product in a series



The four adjacent digits in the 1000-digit number that have the greatest product are 9 x 9 x 8 x 9 = 5832.

73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?

"""

import time
start_time = time.time()

num = "\
73167176531330624919225119674426574742355349194934\
96983520312774506326239578318016984801869478851843\
85861560789112949495459501737958331952853208805511\
12540698747158523863050715693290963295227443043557\
66896648950445244523161731856403098711121722383113\
62229893423380308135336276614282806444486645238749\
30358907296290491560440772390713810515859307960866\
70172427121883998797908792274921901699720888093776\
65727333001053367881220235421809751254540594752243\
52584907711670556013604839586446706324415722155397\
53697817977846174064955149290862569321978468622482\
83972241375657056057490261407972968652414535100474\
82166370484403199890008895243450658541227588666881\
16427171479924442928230863465674813919123162824586\
17866458359124566529476545682848912883142607690042\
24219022671055626321111109370544217506941658960408\
07198403850962455444362981230987879927244284909188\
84580156166097919133875499200524063689912560717606\
05886116467109405077541002256983155200055935729725\
71636269561882670428252483600823257530420752963450"

def digit_product(slice_size):
	product = 1
	for i in xrange(len(slice_size)):
		product = product * int(slice_size[i])
	return product

#print digit_product("9989")

def slicer(num, slice_size):
	if len(num) < slice_size:
		print "The number given is smaller than the slice size"
		return None
	
	max_product = 0
	for i in xrange(len(num) - slice_size):
		product = digit_product(num[i: i + slice_size])
		if max_product <= product:
			max_product =  product
			max_i = i

	print max_i
	for j in xrange(max_i, max_i + slice_size):
		print num[j],
	print 
	return max_product

print slicer(num, 13)


print "Time elapsed: %5.3f" % (time.time() - start_time)

"""
answer is 23514624000 
it's the 13 digits atarting from the 197th digit - 
5 5 7 6 6 8 9 6 6 4 8 9 5
"""
d402d8d99a4df6b058102549bb96c511c655446c
"""
Largest product in a series



The four adjacent digits in the 1000-digit number that have the greatest product are 9 x 9 x 8 x 9 = 5832.

73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?

"""

import time
start_time = time.time()

num = "\
73167176531330624919225119674426574742355349194934\
96983520312774506326239578318016984801869478851843\
85861560789112949495459501737958331952853208805511\
12540698747158523863050715693290963295227443043557\
66896648950445244523161731856403098711121722383113\
62229893423380308135336276614282806444486645238749\
30358907296290491560440772390713810515859307960866\
70172427121883998797908792274921901699720888093776\
65727333001053367881220235421809751254540594752243\
52584907711670556013604839586446706324415722155397\
53697817977846174064955149290862569321978468622482\
83972241375657056057490261407972968652414535100474\
82166370484403199890008895243450658541227588666881\
16427171479924442928230863465674813919123162824586\
17866458359124566529476545682848912883142607690042\
24219022671055626321111109370544217506941658960408\
07198403850962455444362981230987879927244284909188\
84580156166097919133875499200524063689912560717606\
05886116467109405077541002256983155200055935729725\
71636269561882670428252483600823257530420752963450"

def digit_product(slice_size):
	product = 1
	for i in xrange(len(slice_size)):
		product = product * int(slice_size[i])
	return product

#print digit_product("9989")

def slicer(num, slice_size):
	if len(num) < slice_size:
		print "The number given is smaller than the slice size"
		return None
	
	max_product = 0
	for i in xrange(len(num) - slice_size):
		product = digit_product(num[i: i + slice_size])
		if max_product <= product:
			max_product =  product
			max_i = i

	print max_i
	for j in xrange(max_i, max_i + slice_size):
		print num[j],
	print 
	return max_product

print slicer(num, 13)


print "Time elapsed: %5.3f" % (time.time() - start_time)

"""
answer is 23514624000 
it's the 13 digits atarting from the 197th digit - 
5 5 7 6 6 8 9 6 6 4 8 9 5
"""