"""
    304. 2018-8-16 23:35:11
    Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2).

    Range Sum Query 2D
    The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2) = (4, 3), which contains sum = 8.

    Example:
    Given matrix = [
      [3, 0, 1, 4, 2],
      [5, 6, 3, 2, 1],
      [1, 2, 0, 1, 5],
      [4, 1, 0, 1, 7],
      [1, 0, 3, 0, 5]
    ]

    sumRegion(2, 1, 4, 3) -> 8
    sumRegion(1, 1, 2, 2) -> 11
    sumRegion(1, 2, 2, 4) -> 12
    Note:
    You may assume that the matrix does not change.
    There are many calls to sumRegion function.
    You may assume that row1 ≤ row2 and col1 ≤ col2.
    这题也能是Medium
"""


class NumMatrix:
    def __init__(self, matrix):
        self._matrix = matrix

    def sumRegion(self, row1, col1, row2, col2):
        regionSum = 0
        for i in range(row1, row2 + 1):
            regionSum += sum(self._matrix[i][col1:col2+1])

        return regionSum


matrix1 = [
    [3, 0, 1, 4, 2],
    [5, 6, 3, 2, 1],
    [1, 2, 0, 1, 5],
    [4, 1, 0, 1, 7],
    [1, 0, 3, 0, 5]
]
instance = NumMatrix(matrix1)

print(instance.sumRegion(2, 1, 4, 3))

3e1ea7653d72de4a14d945c80639d007767c5466
<mask token>


class NumMatrix:
    <mask token>
    <mask token>


<mask token>

<mask token>


class NumMatrix:

    def __init__(self, matrix):
        self._matrix = matrix

    def sumRegion(self, row1, col1, row2, col2):
        regionSum = 0
        for i in range(row1, row2 + 1):
            regionSum += sum(self._matrix[i][col1:col2 + 1])
        return regionSum


<mask token>

<mask token>


class NumMatrix:

    def __init__(self, matrix):
        self._matrix = matrix

    def sumRegion(self, row1, col1, row2, col2):
        regionSum = 0
        for i in range(row1, row2 + 1):
            regionSum += sum(self._matrix[i][col1:col2 + 1])
        return regionSum


<mask token>
print(instance.sumRegion(2, 1, 4, 3))

<mask token>


class NumMatrix:

    def __init__(self, matrix):
        self._matrix = matrix

    def sumRegion(self, row1, col1, row2, col2):
        regionSum = 0
        for i in range(row1, row2 + 1):
            regionSum += sum(self._matrix[i][col1:col2 + 1])
        return regionSum


matrix1 = [[3, 0, 1, 4, 2], [5, 6, 3, 2, 1], [1, 2, 0, 1, 5], [4, 1, 0, 1, 
    7], [1, 0, 3, 0, 5]]
instance = NumMatrix(matrix1)
print(instance.sumRegion(2, 1, 4, 3))

"""
    304. 2018-8-16 23:35:11
    Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2).

    Range Sum Query 2D
    The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, col2) = (4, 3), which contains sum = 8.

    Example:
    Given matrix = [
      [3, 0, 1, 4, 2],
      [5, 6, 3, 2, 1],
      [1, 2, 0, 1, 5],
      [4, 1, 0, 1, 7],
      [1, 0, 3, 0, 5]
    ]

    sumRegion(2, 1, 4, 3) -> 8
    sumRegion(1, 1, 2, 2) -> 11
    sumRegion(1, 2, 2, 4) -> 12
    Note:
    You may assume that the matrix does not change.
    There are many calls to sumRegion function.
    You may assume that row1 ≤ row2 and col1 ≤ col2.
    这题也能是Medium
"""


class NumMatrix:
    def __init__(self, matrix):
        self._matrix = matrix

    def sumRegion(self, row1, col1, row2, col2):
        regionSum = 0
        for i in range(row1, row2 + 1):
            regionSum += sum(self._matrix[i][col1:col2+1])

        return regionSum


matrix1 = [
    [3, 0, 1, 4, 2],
    [5, 6, 3, 2, 1],
    [1, 2, 0, 1, 5],
    [4, 1, 0, 1, 7],
    [1, 0, 3, 0, 5]
]
instance = NumMatrix(matrix1)

print(instance.sumRegion(2, 1, 4, 3))
