# solve the quadratic equation ax**2+bx+c=0
import cmath
a = 1
b = 5
c = 6
#calculate the discriminant
d = (b **2) - (4 * a *c)
# find two solutions
sol1 = (-b - cmath.sqrt(d)) / (2 * a)
sol2 = (-b + cmath.sqrt(d)) / (2 * a)
print('The solution are {0} and {1}'.format(sol1,sol2))
8905a4c8e026087e8e0ad97e93dac1e2165be4f4
<mask token>

<mask token>
print('The solution are {0} and {1}'.format(sol1, sol2))

<mask token>
a = 1
b = 5
c = 6
d = b ** 2 - 4 * a * c
sol1 = (-b - cmath.sqrt(d)) / (2 * a)
sol2 = (-b + cmath.sqrt(d)) / (2 * a)
print('The solution are {0} and {1}'.format(sol1, sol2))

import cmath
a = 1
b = 5
c = 6
d = b ** 2 - 4 * a * c
sol1 = (-b - cmath.sqrt(d)) / (2 * a)
sol2 = (-b + cmath.sqrt(d)) / (2 * a)
print('The solution are {0} and {1}'.format(sol1, sol2))

# solve the quadratic equation ax**2+bx+c=0
import cmath
a = 1
b = 5
c = 6
#calculate the discriminant
d = (b **2) - (4 * a *c)
# find two solutions
sol1 = (-b - cmath.sqrt(d)) / (2 * a)
sol2 = (-b + cmath.sqrt(d)) / (2 * a)
print('The solution are {0} and {1}'.format(sol1,sol2))