In the hypocrite across remains assigned , you have now hard .
(ROOT_0 (S_0 (ATS_3 (ATS_1 (ATS_2 (PP_2 (IN_0 In) (NP_3 (NP_5 (DT_0 the) (NN_2 hypocrite)) (PP_0 (IN_1 across) (NP_2 (NP_4 (NNS_1 remains)) (VP_2 (VBN_0 assigned)))))) (COMMA_0 ,)) (NP_0 (PRP_1 you))) (VP_3 (VBP_0 have) (ADJP_0 (RB_0 now) (JJ_0 hard)))) (DOT_0 .)))