if the given two numbers are respectively 8 % and 16 % of a third number , then what percentage is the first of the second ?
"here , l = 8 and m = 16 therefore , first number = l / m x 100 % of second number = 8 / 16 x 100 % of second number = 50 % of second number answer : d"
multiply(divide(divide(8, const_100), divide(16, const_100)), const_100)