what is the sum of all possible solutions to | x - 3 | ^ 2 + | x - 3 | = 42 ?
"denote | x - 3 | as y : y ^ 2 + y = 42 - - > y = - 7 or y = 6 . discard the first solution since y = | x - 3 | , so it ' s an absolute value and thus can not be negative . y = | x - 3 | = 6 - - > x = 9 or x = - 4 . the sum = 5 . answer : c ."
add(add(const_4, 3), subtract(3, const_4))