every day daniel drives 120 miles back from work . on sunday , daniel drove all the way back from work at a constant speed of x miles per hour . on monday , daniel drove the first 32 miles back from work at ( 2 x ) miles per hour , and the rest of the way at ( x / 2 ) miles per hour . the time it took daniel to drive back from work on monday is longer than the time it took him to drive back from work on sunday by what percent ?
let ' s test x = 4 . . . . on sunday , daniel drove 120 miles at 4 miles / hour . d = ( r ) ( t ) 120 = ( 4 ) ( t ) 120 / 4 = 30 = t it takes 30 hours to drive home on monday , daniel drove the first 32 miles at ( 2 ) ( 4 ) = 8 miles / hour and the rest of the way ( 88 miles ) at 4 / 2 = 2 miles / hour d = ( r ) ( t ) 32 = ( 8 ) ( t ) 32 / 8 = 4 = t it takes 4 hours for the first part d = ( r ) ( t ) 88 = ( 2 ) ( t ) 88 / 2 = 44 = t it takes 44 hours for the second part total time to drive home on monday = 4 + 44 = 48 hours we ' re asked by what percent 48 hours is greater than 30 hours . 48 / 30 = 1.6 , so it is 60 % greater . answer : e
multiply(divide(subtract(add(divide(32, 2), multiply(subtract(120, 32), const_2)), 120), 120), const_100)