in how many ways 4 boys and 5 girls can be seated in a row so that they are alternate .
"solution : let the arrangement be , g b g b g b g b g 4 boys can be seated in 4 ! ways . girl can be seated in 3 ! ways . required number of ways , = 4 ! * 5 ! = 2880 . answer : option e"
multiply(factorial(4), factorial(5))