a soccer store typically sells replica jerseys at a discount of 30 percent to 40 percent off list price . during the annual summer sale , everything in the store is an additional 20 percent off the original list price . if a replica jersey ' s list price is $ 80 , approximately what percent of the list price is the lowest possible sale price ?
"let the list price be 2 x for min sale price , the first discount given should be 50 % , 2 x becomes x here now , during summer sale additional 20 % off is given ie sale price becomes 0.8 x it is given lise price is $ 80 = > 2 x = 80 = > x = 30 and 0.8 x = 32 so lowest sale price is 32 , which is 40 % of 80 hence , c is the answer"
divide(80, const_2)