if the sum of two positive integers is 18 and the difference of their squares is 36 , what is the product of the two integers ?
"let the 2 positive numbers x and y x + y = 18 - - 1 x ^ 2 - y ^ 2 = 36 = > ( x + y ) ( x - y ) = 36 - - 2 using equation 1 in 2 , we get = > x - y = 2 - - 3 solving equation 1 and 3 , we get x = 10 y = 8 product = 10 * 8 = 80 answer b"
multiply(divide(subtract(18, divide(36, 18)), divide(36, 18)), add(divide(subtract(18, divide(36, 18)), divide(36, 18)), divide(36, 18)))