the calendar of the year 2080 can be used again in the year ?
"explanation : given year 2080 when divided by 4 , leaves a remainder 0 . note : when remainder is 0 , 28 is added to the given year to get the result . so , 2080 + 28 = 2108 answer : e"
add(multiply(subtract(multiply(const_4, const_4), const_2), const_2), 2080)