one day a car rental agency rented 2 / 3 of its cars , including 3 / 5 of its cars with cd players . if 3 / 5 of its cars have cd players , what percent of the cars that were not rented had cd players ?
"the cars with cd players which were not rented is ( 2 / 5 ) ( 3 / 5 ) = 6 / 25 of all the cars . the cars which were not rented is 1 / 3 of all the cars . the percent of non - rented cars which had cd players is ( 6 / 25 ) / ( 1 / 3 ) = 18 / 25 the answer is a ."
multiply(divide(subtract(divide(multiply(3, multiply(multiply(3, 3), 5)), 5), divide(multiply(divide(multiply(3, multiply(multiply(3, 3), 5)), 5), 3), 3)), subtract(multiply(multiply(3, 3), 5), divide(multiply(2, multiply(multiply(3, 3), 5)), 3))), const_100)