the amounts of time that three secretaries worked on a special project are in the ratio of 1 to 2 to 5 . if they worked a combined total of 120 hours , how many hours did the secretary who worked the longest spend on the project ?
"8 x = 120 = > x = 15 therefore the secretary who worked the longest spent 15 x 5 = 75 hours on the project option ( c )"
multiply(divide(120, add(add(1, 2), 5)), 5)