micheal and adam can do together a piece of work in 20 days . after they have worked together for 16 days micheal stops and adam completes the remaining work in 10 days . in how many days micheal complete the work separately .
"rate of both = 1 / 20 together they do = 1 / 20 * 16 = 4 / 5 left work = 1 - 4 / 5 = 1 / 5 adam completes 1 / 5 work in 10 day so he took 10 * 5 = 50 days to complete the left work alone . thus the rate of adam is 1 / 50 rate of micheal = 1 / 20 - 1 / 50 = 1 / ( 100 / 3 ) thus micheal takes 100 / 3 days to complete the whole work . ans . b ."
inverse(subtract(inverse(20), inverse(multiply(inverse(subtract(const_1, multiply(inverse(20), 16))), 10))))