2 + 2 + 2 ² + 2 ³ . . . + 2 ^ 10
"2 + 2 = 2 ^ 2 2 ^ 2 + 2 ^ 2 = ( 2 ^ 2 ) * ( 1 + 1 ) = 2 ^ 3 2 ^ 3 + 2 ^ 3 = ( 2 ^ 3 ) * ( 1 + 1 ) = 2 ^ 4 so you can notice the pattern . . . in the end you will have 2 ^ 10 + 2 ^ 10 , which will give you 2 ^ 11 answer c"
divide(multiply(2, add(2, 2)), 2)