how many numbers between 100 and 630 are divisible by 2 , 3 , and 7 together ?
"explanation : as the division is by 2 , 3 , 7 together , the numbers are to be divisible by : 2 * 3 * 7 = 42 the limits are 100 and 600 the first number divisible is 42 * 3 = 126 to find out the last number divisible by 42 within 630 : 630 / 42 = 13 hence , 42 * 15 = 630 is the last number divisible by 42 within 630 hence , total numbers divisible by 2 , 3 , 7 together are ( 15 â € “ 2 ) = 13 answer : d"
subtract(divide(630, multiply(multiply(2, 3), 7)), divide(100, multiply(multiply(2, 3), 7)))