in a simultaneous throw of a pair of dice , find the probability of getting a total more than 8
"total number of cases = 7 * 7 = 49 favourable cases = [ ( 2,7 ) , ( 3,6 ) , ( 3,7 ) , ( 4,5 ) , ( 4,6 ) , ( 4,7 ) , ( 5,4 ) , ( 5,5 ) , ( 5,6 ) , ( 5,7 ) , ( 6,3 ) , ( 6,4 ) , ( 6,5 ) , ( 6,6 ) , ( 6,7 ) , ( 7,2 ) , ( 7,3 ) , ( 7,4 ) , ( 7,5 ) , ( 7,6 ) , ( 7,7 ) ] = 21 so probability = 21 / 49 = 3 / 7 answer is c"
divide(subtract(8, multiply(const_2, const_3)), 8)