if the given two numbers are respectively 7 % and 14 % of a third number , then what percentage is the first of the second ?
"here , l = 7 and m = 14 therefore , first number = l / m x 100 % of second number = 7 / 14 x 100 % of second number = 50 % of second number answer : d"
multiply(divide(divide(7, const_100), divide(14, const_100)), const_100)