the sum of the present ages of two persons a and b is 60 . if the age of a is twice that of b , find the sum of their ages 2 years hence ?
"explanation : a + b = 60 , a = 2 b 2 b + b = 60 = > b = 20 then a = 40 . 2 years , their ages will be 42 and 22 . sum of their ages = 42 + 22 = 64 . c )"
add(add(multiply(divide(60, 2), const_2), 2), add(divide(60, 2), 2))