a fair coin is tossed 9 times . what is the probability of getting more heads than tails in 9 tosses ?
"on each toss , the probability of getting a head is 1 / 2 and the probability of getting a tail is 1 / 2 . there is no way to get the same number of heads and tails on an odd number of tosses . there will either be more heads or more tails . then there must be more heads on half of the possible outcomes and more tails on half of the possible outcomes . p ( more heads ) = 1 / 2 the answer is a ."
divide(add(add(add(choose(9, const_2), choose(9, const_3)), choose(9, const_4)), choose(9, 9)), power(const_2, 9))