what is the greater of the two numbers whose product is 2560 , given that the sum of the two numbers exceeds their difference by 64 ?
let the greater and the smaller number be g and s respectively . gs = 2560 g + s exceeds g - s by 64 i . e . , g + s - ( g - s ) = 64 i . e . , 2 s = 64 = > s = 32 . g = 2560 / s = 80 . answer : e
divide(2560, multiply(power(const_2, const_4), const_2))