one day a car rental agency rented 3 / 4 of its cars , including 2 / 3 of its cars with cd players . if 3 / 5 of its cars have cd players , what percent of the cars that were not rented had cd players ?
"the cars with cd players which were not rented is ( 1 / 3 ) ( 3 / 5 ) = 1 / 5 of all the cars . the cars which were not rented is 1 / 4 of all the cars . the percent of non - rented cars which had cd players is ( 1 / 5 ) / ( 1 / 4 ) = 4 / 5 the answer is d ."
multiply(divide(subtract(divide(multiply(4, multiply(multiply(4, 2), 3)), 3), divide(multiply(divide(multiply(4, multiply(multiply(4, 2), 3)), 3), 4), 2)), subtract(multiply(multiply(4, 2), 3), divide(multiply(3, multiply(multiply(4, 2), 3)), 4))), const_100)