a man is 22 years older than his son . in two years , his age will be twice the age of his son . what is the present age of his son ?
"let present age of the son = x years then , present age the man = ( x + 22 ) years given that , in 2 years , man ' s age will be twice the age of his son â ‡ ’ ( x + 22 ) + 2 = 2 ( x + 2 ) â ‡ ’ x = 20 answer : d"
divide(subtract(22, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1))