a mixture of 125 gallons of wine and water contains 20 % of water . how much water must be added to the mixture in order to increase the percentage of water to 25 % of the new mixture ?
in 125 gallons of the solution there are 0.2 ∗ 125 = 25 gallons of water . we want to add w gallons of water to 125 gallons of solution so that 25 + w gallons of water to be 25 % of new solution : 25 + w = 0.25 ( 125 + w ) - - > w = 253 ≈ 8.33 . answer : d
divide(subtract(multiply(divide(multiply(divide(20, const_100), 125), const_100), 125), 25), subtract(const_1, divide(multiply(divide(20, const_100), 125), const_100)))