an engineer undertakes a project to build a road 10 km long in 300 days and employs 30 men for the purpose . after 100 days , he finds only 2 km of the road has been completed . find the ( approximate ) number of extra men he must employ to finish the work in time .
30 workers working already let x be the total men required to finish the task in next 200 days 2 km done hence remaining is 8 km also , work has to be completed in next 200 days ( 300 - 100 = 200 ) we know that , proportion of men to distance is direct proportion and , proportion of men to days is inverse proportion hence , x = ( 30 * 8 * 100 ) / ( 2 * 200 ) thus , x = 60 thus , more men needed to finish the task = 60 - 30 = 30 answer : c
subtract(divide(multiply(multiply(30, subtract(10, 2)), 100), multiply(2, subtract(300, 100))), 30)