the cyclist going at a constant rate of 20 miles per hour is passed by a motor - cyclist traveling in the same direction along the same path at 60 miles per hour . the motor - cyclist stops to wait for the cyclist 10 minutes after passing her , while the cyclist continues to travel at constant rate , how many minutes must the motor - cyclist wait until the cyclist catches up ?
"for the 10 minutes the motor - cyclist continues to overtake the cyclist , she is going at 40 miles per hour faster than the cyclist . once the motor - cyclist stops , the cyclist is going at 20 miles per hour while the motor - cyclist is at rest so the amount of time the cyclist will take to cover the distance between them is going to be in the ratio of the relative speeds . 40 / 20 * 10 or 20 minutes answer is ( b )"
divide(multiply(subtract(divide(60, const_4), divide(20, const_4)), const_60), 20)