a can do a piece of work in 15 days . a does the work for 5 days only and leaves the job . b does the remaining work in 10 days . in how many days b alone can do the work ?
"explanation : a ’ s 5 day work = 5 * 1 / 15 = 1 / 3 remaining work = 1 - 1 / 3 = 2 / 3 b completes 2 / 3 work in 6 days b alone can do in x days 2 / 3 * x = 10 x = 15 days answer : option b"
inverse(multiply(inverse(10), subtract(const_1, multiply(5, inverse(15)))))