the difference between two numbers is 1365 . when the larger number is divided by the smaller one , the quotient is 6 and the remainder is 15 . the smaller number is :
"solution let the numbers be x and ( x + 1365 ) . then , x + 1365 = 6 x + 15 ⇔ 5 x = 1350 ⇔ x = 270 . answer b"
divide(subtract(1365, 15), subtract(6, const_1))