a train leaves mumabai at 9 am at a speed of 45 kmph . after one hour , another train leaves mumbai in the same direction as that of the first train at a speed of 90 kmph . when and at what distance from mumbai do the two trains meet ?
"when the second train leaves mumbai the first train covers 45 * 1 = 45 km so , the distance between first train and second train is 45 km at 10.00 am time taken by the trains to meet = distance / relative speed = 45 / ( 90 - 45 ) = 1 hours so , the two trains meet at 2 p . m . the two trains meet 1 * 90 = 90 km away from mumbai . answer : c"
multiply(divide(multiply(45, const_1), subtract(90, 45)), 90)