find the area of a right - angled triangle whose base is 12 cm and hypotenuse is 13 cm .
sol . height of the triangle = [ ( 13 ) 2 - ( 12 ) 2 ] ( 1 / 2 ) cm = ( 25 ) ( 1 / 2 ) cm = 5 cm . its area = ( 1 / 2 ) * base * height = ( ( 1 / 2 ) * 12 * 5 ) cm ^ 2 = 30 cm ^ 2 . ans : b
triangle_area(12, sqrt(subtract(power(13, const_2), power(12, const_2))))