x varies inversely as square of y . given that y = 2 for x = 1 . the value of x for y = 6 will be equal to :
"given x = k / y 2 , where k is a constant . now , y = 2 and x = 1 gives k = 4 . x = 4 / y 2 = > x = 4 / 62 , when y = 6 = > x = 4 / 36 = 1 / 9 . answer : d"
divide(multiply(1, power(2, const_2)), power(6, const_2))