if the given two numbers are respectively 6 % and 18 % of a third number , then what percentage is the first of the second ?
"here , l = 6 and m = 18 therefore , first number = l / m x 100 % of second number = 6 / 18 x 100 % of second number = 33 1 / 3 % of second number answer : d"
multiply(divide(divide(6, const_100), divide(18, const_100)), const_100)