let f ( x ) = x ^ 2 + bx + c . if f ( 1 ) = 0 and f ( - 6 ) = 0 , then f ( x ) crosses the y - axis at what y - coordinate ?
when x = 1 and when x = - 6 , the expression f ( x ) = x ² + bx + c equals 0 . then f ( x ) = ( x - 1 ) ( x + 6 ) f ( 0 ) = - 6 the answer is a .
negate(divide(subtract(power(6, const_2), const_1), add(6, const_1)))