a , b and c can do a piece of work in 24 days , 30 days and 40 days respectively . they began the work together but c left 6 days before the completion of the work . in how many days was the work completed ?
"one day work of a , b and c = 1 / 24 + 1 / 30 + 1 / 40 = 1 / 10 work done by a and b together in the last 6 days = 6 * ( 1 / 24 + 1 / 30 ) = 9 / 20 remaining work = 11 / 20 the number of days required for this initial work = 5.5 days . the total number of days required = 6 + 5.5 = 11.5 days . answer : d"
add(divide(subtract(const_1, multiply(add(divide(const_1, 24), divide(const_1, 30)), 6)), add(divide(const_1, multiply(add(const_2, const_3), multiply(const_2, 6))), add(divide(const_1, 24), divide(const_1, 30)))), 6)