the mean of 50 observations was 36 . it was found later that an observation 45 was wrongly taken as 23 . the corrected new mean is
"solution correct sum = ( 36 x 50 + 45 - 23 ) = 1822 . â ˆ ´ correct mean = 1822 / 50 = 36.44 . answer d"
divide(add(multiply(36, 50), subtract(subtract(50, const_2), 23)), 50)