the l . c . m . of two numbers is 48 . the numbers are in the ratio 2 : 3 . then sum of the number is :
"let the numbers be 2 x and 3 x . then , their l . c . m . = 6 x . so , 6 x = 48 or x = 8 . the numbers are 16 and 24 . hence , required sum = ( 16 + 24 ) = 40 . answer : option c"
add(multiply(divide(48, multiply(2, 3)), 3), multiply(divide(48, multiply(2, 3)), 2))