the sum of the first 50 positive even integers is 2,000 . what is the sum of the odd integers from 101 to 200 , inclusive ?
"101 + 103 + . . . . . . . 199 if we remove 100 from each of these it will be sum of 1 st 100 odd numbers . so 101 + 103 + . . . . . . . 199 = 50 * 100 + ( 1 + 3 + 5 + 7 + . . . . . . ) sum of 1 st 100 natural numbers = ( 100 * 101 ) / 2 = 5050 sum of 1 st 50 positive even integers = 2000 sum of 1 st 100 odd numbers = 5050 - 2000 = 3050 so 101 + 103 + . . . . . . . 199 = 50 * 100 + ( 1 + 3 + 5 + 7 + . . . . . . ) = 5000 + 3050 = 8050 c is the answer ."
multiply(divide(add(200, 101), const_2), add(divide(subtract(200, 101), const_2), const_1))