before 5 years , dog a ’ s age was 4 times of dog b ’ s age and after 4 years , dog a ’ s age will be 3 times of dog b ’ s age . what is the difference of dog a ’ s age and dog b ’ s now ?
"a - 5 = 4 ( b - 5 ) - - > a - 4 b = - 15 . . . . . . . . . . . . . 1 a + 4 = 3 ( b + 4 ) - - > a - 3 b = 8 . . . . . . . . . . . . . 2 ( 2 ) - ( 1 ) - - > b = 23 - - > a = 3 ( 27 ) = 81 a - b = 81 - 23 = 58 answer : c"
subtract(subtract(multiply(4, add(subtract(multiply(4, 4), 4), subtract(multiply(4, 5), 5))), subtract(multiply(4, 5), 5)), add(subtract(multiply(4, 4), 4), subtract(multiply(4, 5), 5)))