let f ( x ) = x ^ 2 + bx + c . if f ( 4 ) = 0 and f ( - 3 ) = 0 , then b + c =
"f ( x ) = x ^ 2 + bx + c . if f ( 4 ) = 0 and f ( - 3 ) = 0 , then b + c = f ( 4 ) = 0 = 16 + 4 b + c - - - taking 16 to the other side - > 4 b + c = - 16 f ( - 3 ) = 0 = 9 - 3 b + c - - - taking - 3 b + c to the other side - > 3 b - c = 9 when we add these 2 equations , we get 7 b = - 7 - - - > b = - 1 and while substituting b = - 1 we get c = - 12 . b + c = - 13 - - - answer c"
negate(divide(subtract(power(3, 2), 4), add(3, 4)))