the sum of the ages of 5 children born at the intervals of 3 years each is 80 years . what is the age of the youngest child ?
"let the ages of the children be x , ( x + 3 ) , ( x + 6 ) , ( x + 9 ) and ( x + 12 ) years . then , x + ( x + 3 ) + ( x + 6 ) + ( x + 9 ) + ( x + 12 ) = 80 5 x = 50 = > x = 10 . age of youngest child = x = 10 years . answer : e"
divide(subtract(divide(80, divide(5, 3)), multiply(subtract(5, const_1), 3)), 3)