working alone at their respective constant rates , a can complete a task in ‘ a ’ days and b in ‘ b ’ days . they take turns in doing the task with each working 2 days at a time . if a starts they finish the task in exactly 14 days . if b starts , they take a day more . how long does it take to complete the task if they both work together ?
"work done by ab in a day = xy respectively . when a starts : no . of days when a works = 8 no . of days when b works = 6 → 8 x + 6 y = 1 when b starts : no . of days when a works = 7 no . of days when a works = 7 → 7 x + 7 y = 1 solving the above two equations for xy x = 1 / 14 y = 1 / 14 → total work done by ab in a day = 1 / 14 + 1 / 14 = 2 / 28 = 1 / 14 → no . of days to complete the work when both work together = 14 answer : b"
inverse(add(inverse(subtract(14, const_1)), inverse(add(14, 2))))