in a certain corporation , there are 300 male employees and 150 female employees . it is known that 10 % of the male employees have advanced degrees and 40 % of the females have advanced degrees . if one of the 450 employees is chosen at random , what is the probability this employee has an advanced degree or is female ?
p ( female ) = 150 / 450 = 1 / 3 p ( male with advanced degree ) = 0.1 * 300 / 450 = 30 / 450 = 1 / 15 the sum of the probabilities is 6 / 15 = 2 / 5 the answer is c .
add(divide(multiply(subtract(const_1, divide(40, multiply(10, 10))), 150), 450), divide(add(multiply(divide(10, multiply(10, 10)), 300), multiply(divide(40, multiply(10, 10)), 150)), 450))