a is twice as good a work man as b and together they finish a piece of work in 16 days . the number of days taken by a alone to finish the work is :
"solution ( a ’ s 1 day ’ s work ) : ( b ’ s 1 day ’ s work ) = 2 : 1 . ( a + b ) ' s 1 day ’ s work = 1 / 16 divide 1 / 14 in the ratio 2 : 1 . ∴ a ’ s 1 day ’ s work = ( 1 / 14 x 2 / 3 ) = 1 / 24 hence , a alone can finish the work in 24 days . answer b"
inverse(divide(inverse(16), add(const_2, const_1)))