a can finish a work in 6 days and b can do the same work in 15 days . b worked for 10 days and left the job . in how many days , a alone can finish the remaining work ?
"b ' s 10 day ' s work = ( 1 x 10 ) = 2 . 15 3 remaining work = ( 1 - 2 ) = 1 . 3 3 now , 1 work is done by a in 1 day . 6 therefore 1 work is done by a in ( 6 x 1 ) = 2 days . d"
divide(multiply(multiply(divide(const_1, 15), 10), 6), const_2)