what will be remainder when ( 67 ^ 67 + 67 ) is divided by 68 ?
( xn + 1 ) will be divisible by ( x + 1 ) only when n is odd . ( 67 ^ 67 + 1 ) will be divisible by ( 67 + 1 ) ( 67 ^ 67 + 1 ) + 66 , when divided by 68 will give 66 as remainder . b )
add(67, power(subtract(67, 68), 67))