two stations a and b are 110 km apart on a straight line . one train starts from a at 8 a . m . and travels towards b at 20 kmph . another train starts from b at 8 a . m . and travels towards a at a speed of 25 kmph . at what time will they meet ?
"suppose they meet x hours after 8 a . m . distance covered by a in x hours = 20 x km . distance covered by b in ( x - 1 ) hours = 25 ( x - 1 ) km . therefore 20 x + 25 ( x - 1 ) = 110 45 x = 135 x = 3 . so , they meet at 11 a . m . answer : a"
add(8, divide(subtract(110, 20), add(25, 20)))