if two positive numbers are in the ratio 1 / 12 : 1 / 9 , then by what percent is the second number more than the first ?
"given ratio = 1 / 12 : 1 / 9 = 9 : 12 let first number be 9 x and the second number be 12 x . the second number is more than first number by 3 x . required percentage = 3 x / 9 x * 100 = 33.33 % . answer : c"
multiply(divide(1, 9), const_100)