in the junior basketball league there are 15 teams , 1 / 3 of them are bad and ½ are rich . what ca n ' t be the number of teams that are rich and bad ?
"total teams = 15 bad teams = ( 1 / 3 ) * 15 = 5 rich teams = 8 so maximum value that the both rich and bad can take will be 8 . so e = 9 can not be that value . ans e ."
add(multiply(15, divide(const_1, 1)), const_1)