how many 0 ' s are there in the binary form of 6 * 1024 + 4 * 64 + 2
6 * 1024 + 4 * 64 + 2 = 6144 + 256 + 2 = 6402 in binary code 6402 base 10 = 11001 000000 10 in base 2 . so 9 zeros are there . answer : e
subtract(add(6, 4), const_1)