a shop produces sarongs . the daily average production is given by 5 n + 20 , where n is the number of workers aside from the owner . in the first k days , 500 units are produced , and then 5 workers are added to the team . after another k days , the cumulative total is 900 . how many workers were part of the latter production run ?
"the daily average production is given by 5 n + 20 - given in the first k days , 500 units are produced = ( 5 n + 20 ) k = 500 k = 500 / 5 n + 20 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1 5 workers were added = 5 ( n + 5 ) + 20 = 5 n + 45 cumulative is 900 . . thus for the current period = 900 - 500 = 400 ( 5 n + 45 ) k = 400 k = 400 / 5 n + 45 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2 equate 1 and 2 500 / 5 n + 20 = 400 / 5 n + 45 500 ( 5 n + 45 ) = 400 ( 5 n + 20 ) 25 n + 225 = 20 n + 80 5 n = 145 n = 29 thus n + 5 = 34 hence e"
add(20, 5)