if the operation @ is defined for all a and b by the equation a @ b = ( a ^ 2 * b ) * 3 , then 2 @ ( 3 @ - 1 ) =
"work within the parenthesis first so solve ( 3 @ - 1 ) first ( 3 @ - 1 ) = ( ( 3 ^ 2 ) * - 1 ) * 3 = ( 9 * - 1 ) * 3 = - 9 * 3 = - 27 now take - 3 plug back into equation and solve the rest 2 @ ( - 27 ) = ( ( 2 ^ 2 ) * - 3 ) * 3 = ( 4 * - 27 ) * 3 = - 324 so - 324 is the answer . . . . this question is merely testing order of operations remember pemdas option a"
subtract(2, 3)