3 / [ ( 1 / 0.03 ) + ( 1 / 0.37 ) ] = ?
"approximate . 1 / . 03 = 100 / 3 = 33 1 / . 37 = 100 / 37 = 3 denominator becomes 33 + 3 = 36 3 / 36 = . 08 something answer ( b )"
inverse(add(divide(3, 0.03), divide(3, 0.37)))