the sum of the ages of 5 children born at the intervals of 3 year each is 40 year . what is the age of the youngest child ?
"solution let the ages of the children be x , ( x + 3 ) , ( x + 6 ) , ( x + 9 ) and ( x + 12 ) year . then , x + ( x + 3 ) + ( x + 6 ) + ( x + 9 ) + ( x + 12 ) = 40 â ‡ ” 5 x = 10 â ‡ ” x = 2 . â ˆ ´ age of the youngest child = x = 2 years . answer a"
divide(subtract(divide(40, divide(5, 3)), multiply(subtract(5, const_1), 3)), 3)