the sum of the numbers is 330 . if the first number be twice the second and third number be one - third of the first , then the second number is :
"let the second number be x . then , first number = 2 x and third number = 2 x / 3 . 2 x + x + 2 x / 3 = 330 11 x / 3 = 330 x = 90 answer : e"
divide(multiply(330, const_3), add(const_10, const_1))