at a small company , 61 percent of the employees are women , and 60 percent of the employees are married . if 2 / 3 of the men are single , what fraction of the women are married ?
"lets take total employees are 100 . given that , total women = 61 and total married = 60 . total men = 100 - 61 = 39 and single men = 2 / 3 * 39 = 26 . married men = total men - single men = 39 - 26 = 13 . married women = total married - married men = 60 - 13 = 47 . fraction of women are married = married women / total women = 47 / 61 = 5 / 7 . ans d"
divide(subtract(divide(60, const_100), multiply(subtract(const_1, divide(61, const_100)), subtract(const_1, divide(2, 3)))), divide(61, const_100))