a sum was put a simple interest at a certain rate for 4 years . had it been put at 3 % higher rate , it would have fetched rs . 120 more . the sum is :
explanation : let the sub be rs . x and the initial rate be r % . then x ã — ( r + 3 ) ã — 4 / 100 â ˆ ’ x ã — r ã — 4 / 100 = 120 â ‡ ’ x ã — 3 ã — 4 / 100 = 120 â ‡ ’ x ã — 4 / 100 = 40 â ‡ ’ 4 x = 4000 â ‡ ’ x = 1000 answer : option b
multiply(divide(divide(120, 4), 3), const_100)