4 / [ ( 1 / 0.03 ) + ( 1 / 0.37 ) ] = ?
"approximate . 1 / . 03 = 100 / 3 = 33 1 / . 37 = 100 / 37 = 3 denominator becomes 33 + 3 = 36 4 / 36 = . 1111 answer ( b )"
inverse(add(divide(4, 0.03), divide(4, 0.37)))