rs . 6000 is lent out in two parts . one part is lent at 7 % p . a simple interest and the other is lent at 10 % p . a simple interest . the total interest at the end of one year was rs . 480 . find the ratio of the amounts lent at the lower rate and higher rate of interest ?
"let the amount lent at 7 % be rs . x amount lent at 10 % is rs . ( 6000 - x ) total interest for one year on the two sums lent = 7 / 100 x + 10 / 100 ( 6000 - x ) = 600 - 3 x / 100 = > 600 - 3 / 100 x = 480 = > x = 5000 amount lent at 10 % = 2000 required ratio = 2000 : 1000 = 2 : 1 answer : a"
divide(divide(subtract(multiply(480, const_100), multiply(6000, 7)), subtract(10, 7)), divide(subtract(multiply(480, const_100), multiply(6000, 7)), subtract(10, 7)))