in the xy - plane the point ( - 2 - 3 ) is the centre of a circle , the point ( - 2 , 3 ) lies inside the circle and the point ( 6 , - 3 ) lies outside the circle . if the radius r of the circle r is an integer then r =
can be solved without much calculations . you are given that ( - 2 , - 3 ) is the center of the circle . point ( 6 , - 3 ) lies inside the circle - - - > the radius is lesser than distance of ( - 2 , - 3 ) from ( 6 , - 3 ) - - - > lesser than 8 units but the radius will also be greater than the distance of ( - 2 , - 3 ) from ( - 2,3 ) - - - - > greater than 6 units . thus the radius is > 6 but < 8 and as it is an integer , the only possible value of radius = 7 units . d is the correct answer .
divide(add(subtract(6, negate(2)), 6), 2)