a dice has one of the first 4 prime number on each its 6 sides , with no two sides having the same number . the dice is rolled 10 times and the results added . the addition is most likely to be closet to
if die is rolled then avg score = ( 2 + 3 + 5 + 7 ) / 4 = 41 / 4 so , most likely sum for 10 times = 41 / 4 * 10 = 43 answer : b
add(add(add(add(add(const_2, divide(6, const_2)), add(const_2, const_3)), add(const_3, const_4)), add(add(const_3, const_4), const_4)), add(const_2, add(add(const_3, const_4), const_4)))