# The external angle at the apex of an isosceles triangle is 48 degrees. find the value of the angle at its base.

Angles ABC and CBD are adjacent, the sum of which is 180, then the angle ABC = (180 – CBD) = 180 – 48 = 132.

In an isosceles triangle, the angles at the base are equal.

Then the angle BAC = CBD = (180 – ABC) / 2 = (180 – 132) / 2 = 48/2 = 24.

Answer: The angle at the base is 24.

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