# Question #ed040

Mar 24, 2017

See below

#### Explanation:

The total mechanical energy, $E$, is the sum of the kinetic energy, $T = \frac{1}{2} m {v}^{2}$, and the potential energy, $V \left(x\right)$ as mentioned.

If all the energy is kinetic, then $\frac{1}{2} {v}^{2} = 2$, as $m = 1$

So, ${v}^{2} = 4 \implies v = \pm 2$

As speed $= \left\mid v \right\mid$, we go with (1)

:)
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