# Triple integral to find volume

• Jul 9th 2011, 08:49 PM
nameck
Triple integral to find volume
Calculate the volume bounded by the surface 9 + x + y = z , z = 1 , x^2 +y^2 = 4?

i try to convert the range into cylindrical coordinate first..

i know the range for phi and r..
i just dont know the range of z..

where i try z is from 0 to 9 + r (dont know whether it is correct or not..)
• Jul 10th 2011, 12:07 AM
Opalg
Re: Triple integral to find volume
Quote:

Originally Posted by nameck
Calculate the volume bounded by the surface 9 + x + y = z , z = 1 , x^2 +y^2 = 4?

i try to convert the range into cylindrical coordinate first..

i know the range for phi and r..
i just dont know the range of z..

where i try z is from 0 to 9 + r (dont know whether it is correct or not..)

This surface is formed from the cylinder $x^2+y^2=4$ by slicing it off at the bottom by the plane z=1, and at the top by the plane z= 9+x+y. So the lower limit for z is 1 (not 0), and the upper limit is $9+x+y$, which you have to write as $9+r(\cos\theta+\sin\theta)$.
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