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# What value of inductance will provide an $X_\text{L}$ of $500\space\Omega$ at a frequency of $159.15\text{ kHz}$? a. $5\text{ H}$. b. $500\space\mu\text{H}$. c. $500\space\text{mH}$. d. $750\space\mu\text{H}$.

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Here we need to determine what value of inductance will provide the given value of inductive reactance for the given frequency.

The opposition to the flow of current provided by an inductor is the inductive reactance of that inductor. The value of inductive reactance is given by the following equation:

$X_\text{L}=2\pi\cdot f\cdot L$

Rearranging the above equation we can write the value of inductance as:

$L=\dfrac{X_\text{L}}{2\pi\cdot f\tag1}$

Here,

$X_\text{L}\to$ Inductive reactance $($Ohms$).$

$f\to$ Frequency of alternating current $($Hertz$).$

$L\to$ Inductance $($Henry$).$

So, using the above equation we can find the value of inductance.

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