# How do you find the perimeter of a triangle when the sides are 4, 12, and sqrt28?

You add them all. The answer is 16 + $2 \sqrt{7}$
You factor out the $\sqrt{28}$, and it becomes $2 \sqrt{7}$. With this, you add this to 4 and 12. You end up getting 16 + $2 \sqrt{7}$.
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