## Elementary Algebra

We know the following equation: $A = .5bh$ Since $b = 3h -1$, we obtain: $51 = .5(3h-1)(h) \\ 102 = 3h^2 -h \\ 3h^2 -h -102 = 0 \\ (h-6)(3h+17)$ Ignoring negative solutions, we find: $h = 6 \\ b = 3h -1 = 3(6) -1 =17$
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