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If z=a+ib satisfies "arg"(-1)=...

# If z=a+ib satisfies "arg"(-1)="arg"(z+3i), then (a-1):b=

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Text Solution

2:11:3-1:3none of these

B
Solution :
We have, <br> "arg"(z-1)="arg"(z+3i) <br> rArr "arg"(a-1)+ib)="arg"(a+(b+i) <br> rArr tan^(-1)b(a-1)=tan^(-1)(b+3)/a <br> rArr ab=(a-1)(b+3) <br> rArr 3(a-1)=b rArr (a-1):b=1:3

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