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# number theory

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Find the value of $$\sum _{n=1}^{99}9876^{n} \text{(mod 100)}$$

Jun 25, 2020

#1
+30915
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As follows:

9876n (mod(100)  = 9876 (mod(100)) = 76

Hence  $$\Sigma_{n=1}^{99}9876^n (\mod(100) ) = 99*76 = 7524$$

Jun 25, 2020
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