# Jika f(x) = x2 + 3x – 4,

Jika f(x) = x2 + 3x – 4, g(x) = x – 4, dan h(x) = 2x + 1, komposisi fungsi (f o g o h)(x) = ….
A.4×2 – 6x – 4
B.4×2 + 6x – 4
C.x2 + 6x – 7
D.x2 + 5x – 3
E.x2 + 4x – 8
Pembahasan:
f(x) = x2 + 3x – 4
g(x) = x – 4
h(x) = 2x + 1
(g o h)(x) = (2x + 1) – 4
= 2x – 3
Sehingga:
(f o g o h)(x)
= f((g o h)(x))
= f(2x – 3)
= (2x – 3)2 + 3(2x – 3) – 4
= 4×2 – 12x + 9 + 6x – 9 – 4
= 4×2 – 6x – 4
Jawaban: A
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