# How do you solve the quadratic x^2+9x+20=0 using any method?

$x = - 4$ or $x = - 5$
Note that $4 + 5 = 9$ and $4 \cdot 5 = 20$
So: $0 = {x}^{2} + 9 x + 20 = \left(x + 4\right) \left(x + 5\right)$
Hence zeros: $- 4 , - 5$
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