Compute the following a) begin{bmatrix}-5 & -4&3&-10&-3&6 6&-10&5&9&4&-1 end{bmatrix}+begin{bmatrix}-7 & 3&10&0&8&8 8&0&4&-3&-8&0 end{bmatrix}b) -5begin{bmatrix}8 & -10&7 0 & -9&710&-5&-101&5&-10 end{bmatrix}c)begin{bmatrix}3 & 0&-8 6 & -4&-26&0&-8-9&-7&-7 end{bmatrix}^T

Compute the following
a) $\left[\begin{array}{cccccc}-5& -4& 3& -10& -3& 6\\ 6& -10& 5& 9& 4& -1\end{array}\right]+\left[\begin{array}{cccccc}-7& 3& 10& 0& 8& 8\\ 8& 0& 4& -3& -8& 0\end{array}\right]$
b) $-5\left[\begin{array}{ccc}8& -10& 7\\ 0& -9& 7\\ 10& -5& -10\\ 1& 5& -10\end{array}\right]$
c)${\left[\begin{array}{ccc}3& 0& -8\\ 6& -4& -2\\ 6& 0& -8\\ -9& -7& -7\end{array}\right]}^{T}$

You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Gennenzip
Part (a)
Given:
$\left[\begin{array}{cccccc}-5& -4& 3& -10& -3& 6\\ 6& -10& 5& 9& 4& -1\end{array}\right]+\left[\begin{array}{cccccc}-7& 3& 10& 0& 8& 8\\ 8& 0& 4& -3& -8& 0\end{array}\right]$
$\left[\begin{array}{cccccc}-5& -4& 3& -10& -3& 6\\ 6& -10& 5& 9& 4& -1\end{array}\right]+\left[\begin{array}{cccccc}-7& 3& 10& 0& 8& 8\\ 8& 0& 4& -3& -8& 0\end{array}\right]$
$=\left[\begin{array}{cccccc}-5+\left(-7\right)& -4+3& 3+10& -10+0& -3+8& 6+8\\ 6+8& -10+0& 5+4& 9+\left(-3\right)& 4+\left(-8\right)& -1+0\end{array}\right]$
$\left[\begin{array}{cccccc}-12& -1& 13& -10& 5& 14\\ 14& -10& 9& 6& -4& -1\end{array}\right]$
Part (b)
Given:
$-5\left[\begin{array}{ccc}8& -10& 7\\ 0& -9& 7\\ 10& -5& -10\\ 1& 5& -10\end{array}\right]$
Using scalar multiplication of matrices.
$-5\left[\begin{array}{ccc}8& -10& 7\\ 0& -9& 7\\ 10& -5& -10\\ 1& 5& -10\end{array}\right]=\left[\begin{array}{ccc}-5\left(8\right)& -5\left(-10\right)& -5\left(7\right)\\ -5\left(0\right)& -5\left(-9\right)& -5\left(7\right)\\ -5\left(10\right)& -5\left(-5\right)& -5\left(-10\right)\\ -5\left(1\right)& -5\left(5\right)& -5\left(-10\right)\end{array}\right]$
$\left[\begin{array}{ccc}-40& 50& -35\\ 0& 45& -35\\ -50& 25& 50\\ -5& -25& 50\end{array}\right]$
Part (c)
Given:
${\left[\begin{array}{ccc}3& 0& -8\\ 6& -4& -2\\ 6& 0& -8\\ -9& -7& -7\end{array}\right]}^{T}$
Transpose of a matrix is obtained by flipping matrix along diagonal,
${\left[\begin{array}{ccc}3& 0& -8\\ 6& -4& -2\\ 6& 0& -8\\ -9& -7& -7\end{array}\right]}^{T}=\left[\begin{array}{cccc}3& 6& 6& -9\\ 0& -4& 0& -7\\ -8& -2& -8& -7\end{array}\right]$
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 19, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 0, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0, "url": "https://plainmath.net/193/compute-following-bmatrix-10594-bmatrix-bmatrix-310088-bmatrix", "fetch_time": 1656206451000000000, "content_mime_type": "text/html", "warc_filename": "crawl-data/CC-MAIN-2022-27/segments/1656103036363.5/warc/CC-MAIN-20220626010644-20220626040644-00034.warc.gz", "warc_record_offset": 516633261, "warc_record_length": 15007, "token_count": 1260, "char_count": 2481, "score": 3.828125, "int_score": 4, "crawl": "CC-MAIN-2022-27", "snapshot_type": "latest", "language": "en", "language_score": 0.41276636719703674, "file_path": "/sailhome/yjruan/project/latent-lm/data/processed/finemath-4plus/finemath-4plus/train-00013-of-00064.parquet"}