# GATE 2015 EE – SET 1 Question 6

Solution :

V = 0.1 V , I1 =50A , I2 = 500 A ⇒ I2 -I1 = 500 -50 = 450A

Therefore , Rsh =$$\frac{V}{I}$$

⇒  Rsh = $$\frac{V}{I_{2}-/I_{1}}$$ ⇒ $$\frac{0.1}{450}$$

⇒ 0.22x 10-3 ⇒ 0.22mΩ
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