# The number of images formed for two mirrors kept perpendicular to each other is :(a) 1(b) 2(c) 3(d) 5

(c) 3

Reason — When two mirrors are kept perpendicular to each other i.e., θ = 90°,

then n = 360\over 90 = 4

n = 4, is even so the number of images is n – 1

Therefore,

n – 1

= 4 – 1

= 3
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