# A projectile is shot at an angle of pi/12  and a velocity of 44 m/s. How far away will the projectile land?

Mar 30, 2016

${x}_{\text{max"=98,67 " }} m$

#### Explanation:

${v}_{i} = 44 \text{ m/s}$

$\alpha = \frac{\pi}{12}$

$2 \cdot \alpha = 2 \cdot \frac{\pi}{12} = \frac{\pi}{6} \text{ } \sin \left(\frac{\pi}{6}\right) = 0 , 5$

${x}_{\text{max}} = \frac{{v}_{i}^{2} \cdot \sin 2 \alpha}{g}$

${x}_{\text{max}} = \frac{{44}^{2} \cdot 0 , 5}{9 , 81}$

${x}_{\text{max"=98,67 " }} m$
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