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Physics by Inquiry

TEXTBOOK SOLUTIONS FOR Physics by Inquiry 1st Edition

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Chapter: Problem:
SAMPLE SOLUTION
Chapter: Problem:
• Step 1 of 4

A.

In the graph, the location of the image is obtained using a ray diagram. To draw the ray diagram we follow the three rules of refraction for convex lens.

(1)An incident ray coming parallel to the principal axis of the convex (converging) lens refracts through the lens and passes through the focal point on the opposite side of the lens.

(2)Incident ray travelling through the focal point on the way to the lens refracts through the lens and then travels parallel to the principal axis.

(3)An incident ray that passes through the centre of the lens continues to travel in the same direction that it was travelling before entering the lens.

In this graph, the image is obtained at distance
• Step 2 of 4

According to thin lens equation,

Here, di is the distance of the image from the lens.

Substitute for and for.

Solve the equation for .

The di obtained is positive so the image obtained is a real image and located on the opposite side of the lens.

The distance of the image is same in both the cases.

• Step 3 of 4

B.

In the graph, the location of the image is obtained using a ray diagram. To draw the ray diagram we follow the three rules of refraction for convex lens.

1) An incident ray coming parallel to the principal axis of the convex (converging) lens refracts through the lens and passes through the focal point on the opposite side of the lens.

2) Incident ray travelling through the focal point on the way to the lens refracts through the lens and then travels parallel to the principal axis.

3) An incident ray that passes through the centre of the lens continues to travel in the same direction that it was travelling before entering the lens.

In this graph, the image is obtained at on the same side of the lens. So it is a virtual image.

• Step 4 of 4

According to thin lens equation,

Where di is the distance of the image from the lens.

Substitute for and for.

Solve the above equation for.

The di obtained is negative so the image obtained is a virtual image and located on the objectâ€™s side of the lens.

The distance of the image is not same in both the cases.

Corresponding Textbook

Physics by Inquiry | 1st Edition
9780471144410ISBN-13: 047114441XISBN: Authors:
Alternate ISBN: 9780471144403, 9780471144410
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