#### In the given circuit diagram, a wire is joining points B and D. The current in this wire is: (current in amperes,A)  Option: 1 2 Option: 2 0 Option: 3 0.4 Option: 4 4

$\\ \text{Reff} = \frac{4}{5} +\frac{6}{5} = 2\Omega \\ i = \frac{20}{2} = 10A$

So after drawing the circuit

$I = \frac{4i}{5} - \frac{3i}{5} = +\frac{i}{5} = 2A$

Hence the option correct option is (1).
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