## 0.5: The equation of the right bisector of the line segment joining the point A(3,-4) and B(5,+6) is O x-y-9 is o Ox+y+9 is o

Question

0.5: The equation of the right bisector of the line
segment joining the point A(3,-4) and B(5,+6) is
O x-y-9 is o
Ox+y+9 is o
2x+2y-9 is 0
x+2y-7 is 0​

in progress 0
1 month 2021-08-20T10:03:41+00:00 1 Answer 0 views 0

1. Step-by-step explanation:

A(1,2) and B(−2,0) are given point

∴ midpoint p=(

2

1+(−2)

,

2

2+0

)

∴ midpoint p=(

2

−1

,1)

Also slope of AB=

−2−1

0−(2)

=

−3

−2

∴ slope of AB=

3

2

slope of line perpendicular to AB=

3

2

−1

=

2

−3

∴ equation of perpendicular bisector

y−1=

2

−3

(x+

2

1

)

∴y−1=

2

−3

(x+

2

1

)

∴2y−2=−3(x+

2

1

)

∴4y−4=−3(2x+1)

∴4y−4=−6x−3

∴4y+6x−4+3=0

6x+4y−1=0

∴ equation of line 6x+4y−1=0
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