Algebra and Trigonometry 10th Edition

$\frac{5+i}{5-i}=4+\frac{5}{3}i$
$\frac{5+i}{5-i}=\frac{5+i}{5-i}\frac{5+i}{5+i}=\frac{(5+i)^2}{(5-i)(5+i)}=\frac{5^2+2(5)i+i^2}{5^2-i^2}=\frac{25+10i-1}{5+1}=\frac{24+10i}{6}=4+\frac{5}{3}i$
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