If a projectile is shot at an angle of pi/4 and at a velocity of 2 m/s, when will it reach its maximum height??

Jan 26, 2016

height = 20 cm

Explanation:

since $k e$ =$\frac{1}{2} m {v}^{2}$
$K . E = \frac{1}{2} m {2}^{2}$
$k . e = 2 m J$

but K.e =workdone=potential energy of the body at maximum height

therefore$2 m = m g h$

2=10h

$h = \frac{1}{5} m$
or$h = 20 c m$
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