Question

# The inverse of the matrix ⎡⎢⎣250011−103⎤⎥⎦ is

A
3155162152
B
3111565522
C
3155162152
D
355162152

Solution

## The correct option is A ⎡⎢⎣3−155−16−21−52⎤⎥⎦The given matrix is ⎡⎢⎣250011−103⎤⎥⎦ Now we know that A−1=1|A|adj(A) |A|=2(3)−5(1)=1 adj(A)=[cof(aij)]T cof(aij)=⎡⎢⎣3−11−156−55−22⎤⎥⎦ [cof(aij)]T=⎡⎢⎣3−155−16−21−52⎤⎥⎦=adj(A) A−1=1|1|×⎡⎢⎣3−155−16−21−52⎤⎥⎦  Mathematics

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