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The equation of the line passi...

# The equation of the line passing through the point (1,2) and perpendicular to the line x+y+1=0 is

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Text Solution

y-x+1=0 y-x-1=0 y-x+2=0 y-x-2=0

B
Solution :
Given point is (1,2)and slope of the required line is 1. <br> because x+y+1=0rArry=-x-1rArrm_1=-11 <br> therefore  slope of the line =(-1)/(-1)=1 <br> therefore Equation of required line is y-2=1(x-1) <br> rArry-2=x-1 <br> rArry-x-1=0

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Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines

Class 11th

Straight Lines
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