# All columns shall be designed for minimum eccentricity l/500 + d/30 = 20 mm.Where, l = ________d = ________.

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1. Effective length of column, Depth of column
2. Unsupported length of column, Lateral Dimension of column
3. Effective length of column, Lateral dimension of column
4. Unsupported length of column, Depth of column

Option 2 : Unsupported length of column, Lateral Dimension of column
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## Detailed Solution

Explanation:

Minimum eccentricity to be considered along a lateral dimension as per Clause 25.4 of IS 456:2000 is equal to the unsupported length of columns/500 plus lateral dimension/30, subject to a minimum of 20 mm.

Minimum eccentricities:

$${e_{\;x\;min}} = {\rm{max}}\left\{ {\begin{array}{*{20}{c}} {\frac{{{\ell _x}}}{{500}} + \frac{D}{{30}}}\\ {20\;mm} \end{array}} \right.$$

$${e_{y\;min}} = {\rm{max}}\left\{ {\begin{array}{*{20}{c}} {\frac{{{\ell _y}}}{{500}} + \frac{b}{{30}}}\\ {20\;mm} \end{array}} \right.$$

x, ℓy = Unsupported length of column

D and b = lateral dimension of the column

Last updated on Feb 21, 2024

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