# How do you approximate log_3 (7/2) given log_3 2=0.6310 and log_3 7=1.7712?

$= 1.1402$
Use the definition $\log \left(\frac{a}{b}\right) = \log a - \log b$
log₃(7/2)=log₃7-log₃2=1.7712-0.6310=1.1402
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