# Capgemini Aptitude Placement Papers - Capgemini Aptitude Interview Questions and Answers updated on 06.Dec.2023

Cost of each eraser = (36 + 8 -40) = Rs.4

Required amount = 15 * 36 + 12 * 45 + 10 * 8 + 5 * 4

540 + 540 + 80 + 20 = Rs.1180

Let total fair rs.2400

C share=10/24*2400=1000

Distance=125 meter speed=50-5=45km/hr=>45*5/18=12.5 m/s

Time=125/12.5=10sec

Speed upstream = 7.5 km ph.

Speed downstream = 10.5 km ph.

Add up to time taken = 105/7.5 + 105/10.5 hours = 24 hours.

B is thrice as fast as C

C covered in 42 minutes

B covered in 42/3=14 min

Since A beats B by 200 m or 25 seconds, it implies that B covers 200 m in 25 seconds.

Hence speed of B = 200/25 = 8 m/s.

A runs B runs C runs

600 meters race 600 m 540 m

500 meters race 500 m 450 m

Coming ratio A runs B runs C runs

300 meters-2700 meters-2430 meters

Unitary A runs B runs C runs

Methods 400m-360m-324m

A beat C by 400- 324=76 meters.

The least number which when divided by different divisors leaving the same remainder in each case

= LCM(different divisors) + remainder left in each case.

Hence the required least number

= LCM(35, 11) + 1 = 386.

20 men in 6 days can build 112 meters

25 men in 30 days can build=112*(25/20)*(3/6)

= 70 meters

Give the times of youngsters a chance to be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

At that point, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Let CP=100, SP=70

Loss= 30/70*100=42.85%

Let the length and the breadth of the floor be l m and b m respectively.

l = b + 200% of b = l + 2b = 3b

Area of the floor = 324/3 = 108 sq m

l b = 108 i.e., l * l/3 = 108

l2 = 324 => l = 18.

Fifteenth August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 jump years + 7 customary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan. Feb. March April May June July Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Add up to number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.

Given day is Sunday.

(5m + 9w)10 = (6m + 12w)8

=> 50m + 90w = 48w + 96 w => 2m = 6w => 1m = 3w 5m + 9w = 5m + 3m = 8m

8 men can do the work in 10 days.

3m +3w = 3m + 1w = 4m

So, 4 men can do the work in (10 * 8)/4 = 20 days.

Let the first number and the second number be F and S respectively.

5/2 F = 48/100 S —-> (1)

S = 1/9 * 1125 = 125

(1) => 5/7 F = 48/100 * 125

=> F = 84

25% of F = 1/4 * 84 = 21.

Speed = 20 m/sec.

Time = 26 sec.

Then, x + 250 /26= 20

x + 250 = 520

x = 270.

Part filled by (A + B + C) in 3 minutes = 3 (1/30+1/20+1/10)= 3*11/60=11/20

Required proportion = 3/10 x 20/11 = 6 /11

Simple interest = (18000 * 4 * 15)/100 = Rs. 10800

Amount = P + I = 18000 + 10800 = Rs. 28800

For dealing with, A got = 5% of Rs. 7400 = Rs. 370.

Equalization = Rs. (7400 - 370) = Rs. 7030.

Proportion of their investment = (6500 x 6): (8400 x 5): (10000 x 3)

= 39000: 42000: 30000

= 13: 14: 10

B's offer = Rs. 7030 x14/37= Rs. 2660.

Every one of the numbers aside from 14 is an odd number.

The number '14' is the main EVEN number.

Assume initially he had x apples.

At that point, (100 - 40)% of x = 420.

60/100 x x = 420

x = 420 x 100 = 700.

8820 —- 441

100 —- ? => 5%

x *105/100 * 105/100 = 8820

x*1.1025=8820

x=8820/1.1025 => 8000

Each number is double the former one with 1 included or subtracted then again.

Along these lines, the following number is (2 x 261 + 1) = 523.

Let the total worth of the stock be Rs. x.

The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50

The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50

Total SP = 11x/50 + 38x/50 = 49x/50

Overall loss = x – 49x/50 = x/50

x/50 = 400 => x = 20000

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = occasion of getting at most two heads.

At that point E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P (E) = n (E)/n(S) = 7/8

Average mark scored by all the three boys =

[64/100 (800) + 36/100 (800) + 44/100 (800)] / 3 = 384

S.I. for 1 year = Rs. (854 - 815) = Rs. 39.

S.I. for a long time = Rs.(39 x 3) = Rs. 117.

Principal = Rs. (815 - 117) = Rs. 698.

The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15

= 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60

Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.

The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k

It is given that A paid Rs. 1125

45k = 1125 => k = 25

246k = 246(25) = Rs. 6150

Thus the total rent paid by all the four agencies is Rs. 6150.

Give the number of notes of every division a chance to be x.

At that point x + 5x + 10x = 480

16x = 480 x = 30.

Consequently, add up to number of notes = 3x = 90

Let x=speed of boat and y=speed of current

=30/ (x + y) =18/(x-y) =5 by solving y=1.2 km/hr

So we have C.P. = 29.50

S.P. = 31.10

Gain = 31.10 - 29.50 = Rs. 1.6

Gain %=( Gain/Cost*100)%

= (1.6/29.50?100)%=5.4%

Relative speed = (120 + 80) km/hr

= 200 x 5/18 m/sec

= 500/9 m/sec.

Let, S = {1, 2, 3, 4, 19, 20}.

Let E = event of getting a few of 3 or 5 = {3, 6, 9, 12, 15, 18, 5, 10, 20}.

P (E) = n (E)/n(S) = 9/20

At that point, remove canvassed upstream in 8 hrs. 48 min = Distance covered downstream in 4 hrs.

X* 8 4 /5= (y x 4)

44/5 x =4y

y = 11/5 x.

Required proportion = y + x/2: y - x /2

= 16/5 x 1/2: 6/5 x 1/2

= 8/5:3/5

= 8: 3.

Give the number of notes of every group a chance to be x.

At that point x + 5x + 10x = 480

16x = 480

x = 30.

Consequently, add up to number of notes = 3x = 90.

25 * 2 * 0.75 = 20/100 * 10/100 * 7.5/100 * x

25 =  1/100 * x => x = 25000

P(SnK) = P(S) + P(K) – P(SnK), where S denotes spade and K denotes king.

P(SnK) = 13/52 + 4/52 – 1/52 = 4/13

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 conventional years + 1 jump year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May

(31 + 28 + 31 + 30 + 28) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Add up to number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

LCM of 16, 20, 25, 45 = 3600

1 * 3600 + 3 = 3603   not divisible by 21

2 * 3600 + 3 = 7203   is divisible by 21
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