# An artificial satellite revolves around the Earth at a distance of 3400 km. Calculate its orbital velocity and period of revolution. Radius of the Earth = 6400 km; g = 9.8 m/s²

2
by Ishi262

2015-09-25T15:04:25+05:30

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v = orbital velocity        we know  g = G M / R²
d  = 3400 + 6400 km = 10000 km

gravitational force = centripetal force
G M m / d²  =  m v² / d
v² = G M / d  = g R² / d
v = R √(g/d)

ω = angular velocity =  v / R = √(g/d)
T = time period = 2π/ ω  = 2 π √(g/d)

substitute the values to get answers.
2015-09-28T22:37:45+05:30
Distance of artificial satellite (d)= 3400 km
Radius of earth(R) = 6400 km = 6.4×10⁶ m
Radius of orbit(r) = R+d = 10,000 km = 10⁷ m
g = 9.8 m/s²
Orbital velocity,
Period of revolution, T = ?

(i) Orbital velocity

(ii) Time period
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