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# Austin and Erica together sold 100 tickets for the play. How many of

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BSchool Forum Moderator
Joined: 26 Feb 2016
Posts: 3040
Location: India
GPA: 3.12
Austin and Erica together sold 100 tickets for the play. How many of  [#permalink]

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03 Oct 2017, 10:47
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25% (medium)

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78% (00:26) correct 22% (00:22) wrong based on 45 sessions

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Austin and Erica together sold 100 tickets for the play. How many of these tickets were sold by Austin

(1) Erica sold 20% of all the tickets sold for the play
(2) Together Austin and Erica sold 25% of all the tickets sold for the play

Source : Wizako GMAT

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DS Forum Moderator
Joined: 22 Aug 2013
Posts: 1342
Location: India
Re: Austin and Erica together sold 100 tickets for the play. How many of  [#permalink]

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03 Oct 2017, 10:54
Given A + E = 100, we have to find A

(1) E = 20% of total tickets, but we don't know the total number of tickets (we cannot assume 100 to be the total tickets sold for the play, as other people apart from Austin and Erica might have sold tickets too). So we cannot find E, thus cannot find A

(2) tickets sold by them = 100 = 25% of total. Thus total tickets for play sold = 400. But this is insufficient to get our answer

Combining, total tickets = 400 and E = 20% of total = 20% of 400 = 80
Thus A = 100-80 = 20. Sufficient!

Manager
Joined: 14 Sep 2016
Posts: 148
Re: Austin and Erica together sold 100 tickets for the play. How many of  [#permalink]

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08 Oct 2017, 07:43
If we take total no. of tickets sold as "n", and it is given that A+E=100

1) E = .20(n) , since we dont know the actual no. of tickets sold this option is insufficient.
2) .25 * n = 100, this gives n = 400. Insufficient

Taking both options together we can derive the no. of tickets sold by A.
Re: Austin and Erica together sold 100 tickets for the play. How many of &nbs [#permalink] 08 Oct 2017, 07:43
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# Austin and Erica together sold 100 tickets for the play. How many of

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