# How do you solve x^2+x-12=0 using the quadratic formula?

May 2, 2018

The answer ${x}_{1} = 3$

${x}_{2} = - 4$

#### Explanation:

$a {x}^{2} + b x + c = 0$

${x}^{2} + x - 12 = 0$

$a = 1 , b = 1 \mathmr{and} c = - 12$

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$x = \frac{- 1 \pm \sqrt{1 + 48}}{2}$

$x = \frac{- 1 \pm 7}{2}$

${x}_{1} = \frac{- 1 + 7}{2} = \frac{6}{2} = 3$

${x}_{2} = \frac{- 1 - 7}{2} = - \frac{8}{2} = - 4$
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