# ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 7 Percentage Ex 7.3

## ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 7 Percentage Ex 7.3

Question 1.
Find the discount and the selling price, when:
(i) the marked price = ₹575, discount = 12%
(ii) the printed price = ₹12750, discount = $$8 \frac{1}{3}$$%
Solution:
(i) Marked price = ₹575,
discount = 12%
∴ Amount of discount = 12% of Rs. 575

Net Sale Price = M.P. – discount
= ₹575 – ₹69 = ₹506
(ii) Marked price = Rs. 12750,

Net sale price = M.P. – discount
= ₹12750 – ₹1062·50
= ₹11687·50

Question 2.
Find the discount and the discount percentage, when:
(i) marked price = ₹780, selling price = ₹721·50
(ii) advertised price = ₹28500, selling price = ₹24510
Solution:
(i) Marked price = ₹780,
Selling price = ₹721·50
Discount = M.P. – selling price
= ₹780 – ₹721·50 = ₹58·50

selling price = ₹24510
Discount = advertised price – selling price
= ₹28500 – ₹24510 = ₹3990.

Question 3.
A notebook is marked at ₹30. Find the price a student pays for a dozen notebooks if he gets 15% discount.
Solution:
Marked price of one notebook = ₹30
Marked price for one dozen notebook
= ₹30 × 12 = ₹360
Discount = 15%
Amount of discount = 15% of M.P.

Hence the student pays = ₹360 – ₹54 = ₹306

Question 4.
A dealer gave 9% discount on an electric fan and charges ₹ 728 from the customer. Find the marked price of the fan.
Solution:
Let the marked price of the fan = ₹ x
Discount = 9%
amount of discount = 9% of ₹ x

Hence marked the price of the fan = ₹800

Question 5.
The list price of an article is ₹800 and a dealer is selling it at a discount of 20%. Find:
(i) the selling price of the article.
(ii) the cost price of the article if he makes 25% profit on selling it.
Solution:
(i) M.P. = ₹800, discount = 20%

Question 6.
A shopkeeper marks his goods at such a price that would give him a profit of 10% after allowing a discount of 12%. If an article is marked at ₹2250, find its:
(i) selling price
(ii) cost price.
Solution:
(i) Marked price of an article = ₹2250
discount = 12%, S.P. = ?

Hence the cost price = ₹1800

Question 7.
A shopkeeper purchased a calculator for ₹650. He sells it at a discount of 20% and still makes a profit of 20%. Find :
(i) the selling price
(ii) marked price
Solution:
(i) C.P. = ₹650, Profit = 20%, S.P. = ?

Hence the seeling price of the calculator = ₹780.
(ii) S.P. = ₹780, discount = 20%, M.P. = ?

Hence the marked price of calculator = ₹975

Question 8.
A shopkeeper buys a dinner set for ₹ 1200 and marks it 80% above the cost price. If he gives 15% discount on it, find :
(i) the marked price
(ii) the selling price
(iii) his profit percentage.
Solution:
(i) C.P. of a dinner set = ₹1200
Marked price
= ₹1200 + 80% of (₹1200)
= ₹[1200 + $$\frac{80}{100}$$ × 12]
= ₹[1200 + 80 × 12]
= ₹[1200 + 960] = ₹2160

(ii) M.P. = ₹2160, discount = 15%,
S.P. = ?
S.P. = $$\left(1-\frac{d}{100}\right)$$ of M.P.

Question 9.
The cost price of an article is ₹1600, which is 20% below the marked price. If the article is sold at a discount of 16%, find :
(i) the marked price
(ii) the selling price
(iii) profit percentage.
Solution:
(i) C.P. = ₹1600
Since the cost price of an article is 20% below the marked price
Let the marked price of an article = ₹x
∴ Cost price = Marked price – 20% of Marked price
⇒ ₹ 1600 = x – 20% of x
⇒ ₹1600 = x – $$\frac{20}{100}$$ × x
⇒ ₹1600 = $$\frac{80x}{100}$$
⇒ x = ₹1600 × $$\frac{100}{80}$$
= ₹20 × 100 = ₹2000
Hence the marked price of an article = ₹2000

(ii) M.P. of ₹2000, discount = 16%,
S.P. = ?

Question 10.
A shopkeeper allows 20% discount on his goods and still earns a profit of 20%. If an article is sold for ₹360, find:
(i) the marked price
(ii) tine cost price.
Solution:
(i) Since the dealer allows a discount of 20%

(ii) Let the cost price of the article be ₹ x
and Profit is 20%

Hence, the cost price of the article = ₹300

Question 11.
The printed price of a refrigerator is ₹28600. A dealer allows two successive discount of 10% and 5%. Find the price which a customer has to pay for the refrigerator.
Solution:
The printed price of refrigerator = ₹28600

Hence the customer has to pay for the refrigerator = ₹24453.

Question 12.
Two dealers have marked an article at the same price. The first dealer allows two successive discounts of 15% and 5%. The other allows for a discount of 20% which is the better offer?
Solution:
Let the marked price of an article = ₹x
For the first dealer

Hence a 20% discount is better to offer.

Question 13.
Find a single discount equivalent to two successive discounts of 30% and 10%.
Solution:
Let the market price of an article be ₹ x
and a single discount of d% be equivalent to giving
successive discounts of 30% and 10%, then

Hence the single discount of 37% is
equivalent to two given successive discounts.
{"found_math": true, "script_math_tex": 0, "script_math_asciimath": 0, "math_annotations": 0, "math_alttext": 0, "mathml": 0, "mathjax_tag": 0, "mathjax_inline_tex": 0, "mathjax_display_tex": 1, "mathjax_asciimath": 0, "img_math": 0, "codecogs_latex": 0, "wp_latex": 0, "mimetex.cgi": 0, "/images/math/codecogs": 0, "mathtex.cgi": 0, "katex": 0, "math-container": 0, "wp-katex-eq": 0, "align": 0, "equation": 0, "x-ck12": 0, "texerror": 0, "url": "https://cbselibrary.com/ml-aggarwal-class-8-solutions-for-icse-maths-chapter-7-ex-7-3/", "fetch_time": 1716190116000000000, "content_mime_type": "text/html", "warc_filename": "crawl-data/CC-MAIN-2024-22/segments/1715971058222.5/warc/CC-MAIN-20240520045803-20240520075803-00809.warc.gz", "warc_record_offset": 141049572, "warc_record_length": 16981, "token_count": 1469, "char_count": 4798, "score": 4.75, "int_score": 5, "crawl": "CC-MAIN-2024-22", "snapshot_type": "latest", "language": "en", "language_score": 0.9061926007270813, "file_path": "/sailhome/yjruan/project/latent-lm/data/processed/finemath-4plus/finemath-4plus/train-00009-of-00064.parquet"}