Question

# If one mole of a monoatomic gas (r=53) is mixed with one mole of a diatomic gas (r=75), the value of â€˜râ€™ of the mixture is

A
1.4
B
1.5
C
1.53
D
3.07

Solution

## The correct option is C 1.5For a mono atomic gas, Cv=3R2 and for a diatomic gas, Cv=5R2. Since one mole of each gas is mixed together, the CV of the mixture will Cv=12[3R2+5R2]=2R As CP=R+CV=R+2R=3R ∴r=CPCV=3R2R=1.5

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