2014-11-13T20:46:24-05:00

For the first one: 6+4x=3(3x+2)-x

First multiply the right side of the problem.

3(3x+2)-2.

According to PEMDAS you would do the parenthesis first.

This would stay the same because the variables are different.

So, multiply before subtracting.

That becomes 9x+6-2.

So the problem as a whole reads as 6+4x=9x-4.

Subtract 4x from both sides.

This would make the problem read as 6=5x-4.

Then, add 4 to both sides to get 10=5x.

To get x alone divide both sides by 5.

X=2

For the second one: -4x+3=-2(2x-1.5)

Do the right side of the problem first.

-2(2x-1.5)

This would make it say -4x+3.

The problem as a whole would say -4x+3=-4x+3.

As you can see both sides are the same, but we're gonna do the problem normally anyways.

So, -3 from both sides.

The problem would then read as -4x=-4x.

Divide both sides by -4 to get x alone.

This would make it equal -x=-x.

That would make it positive, so it would say x=x.
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