##### In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.5y + 8 = 0

The eq. of the plane

0x-5y + 0z = 8

Direction ratio of the normal (0, -5, 0)

= 5

This is the form of

lx + my + nz = d ( d = Distance of the normal from the origin.)

Direction cosine = 0, -1, 0

1
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