# Tan2A = 9/16 হলে Sin2A + SinA + 1-এর মান নির্ণয় করুন।

1. 36/25
2. 49/25
3. 16/25
4. 3/5

Option 2 : 49/25
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## Detailed Solution

প্রদত্ত:

Tan2A = 9/16

অনুসৃত সূত্র:

TanA = p/b

SinA = p/h

h = √(p2 + b2)

p = লম্ব, b = ভূমি ও h = অতিভুজ

গণনা:

TanA = p/b

⇒ Tan2A = p2/b2

⇒ p2/b2 = 9/16

⇒ p/b = √(9/16)

⇒ p/b = 3/4

সুতরাং, h = √(3x2 + 4x2)

⇒ h = √(9x + 16x)

⇒ h = √25x

⇒ h = 5x

SinA = p/h

⇒ SinA = 3x/5x      ----(1)

⇒ Sin2A = (3/5)2

⇒ Sin2A = 9/25      ----(2)

(1) ও (2) থেকে

Sin2A + SinA + 1

⇒ 9/25 + 3/5 +1

∴ Sin2A + SinA + 1 = 49/25

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