## Algebra 2 (1st Edition)

$$\frac{-4x^2-6x-6}{\left(x+1\right)\left(x+3\right)\left(x-3\right)}$$
Creating like denominators and then simplifying, we find: $$\frac{x+2}{\left(x+1\right)\left(x+3\right)}-\frac{5x}{\left(x+3\right)\left(x-3\right)}\\ \frac{\left(x+2\right)\left(x-3\right)-5x\left(x+1\right)}{\left(x+1\right)\left(x+3\right)\left(x-3\right)}\\ \frac{-4x^2-6x-6}{\left(x+1\right)\left(x+3\right)\left(x-3\right)}$$
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