## Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid \$15 more than Will, how m

Question

Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid \$15 more than Will, how much did dinner cost in total?

in progress 0
37 mins 2021-09-15T21:02:23+00:00 1 Answer 0

The dinner cost was
\$
48

Step-by-step explanation:

Let the dinner cost was  \$
x

Will paid  x
/4

Micah paid  1/
4  of remaining
(
1

1
/4
)
x
=
3/4
x

i.e

4
/16x

Sue paid  3/4  of remaining
(
1

1
/4
)
x
=
3/4x

i.e

9/16
x

Sue paid  \$
15  more than Will.

∴  9/16
x  -1
/4
x
=  5/16x=15

or

x=\$48

Will paid  48
/4
=
\$
1
2, Miah paid  4
/16.
48
=
\$
12

,Sue paid  9/16⋅
48=
\$
27

The dinner cost was
\$
48

.
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