What is $4\cdot 6+8\cdot 3-28\div 2$?
Recall that multiplication and division should be done in order from left to right before addition and subtraction.  We have \begin{align*}4\cdot 6+8\cdot 3-28\div 2&=24+24-14.\end{align*}  Now, we rewrite the subtraction as the addition of a negation so that we can use the properties of addition to rearrange the numbers and make the arithmetic easier.  We get \begin{align*}24+24-14&=24+24+(-14) \\ &=24+(-14)+24 \\ &=24-14+24 \\ &=10+24 \\ &=\boxed{34}.\end{align*}
34
Level 1
Prealgebra
Problem: What is $4\cdot 6+8\cdot 3-28\div 2$?
Solution:<|START_OF_LATENT|><|PRIOR_PREFIX|>To solve the expression, first identify the operations involved: multiplication, addition, subtraction, and division. According to the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right), we need to perform multiplication and division before addition and subtraction.

Start with the multiplication and division in the expression:

1. Calculate $4 \cdot 6$. This equals $24$.
2. Calculate $8 \cdot 3$. This equals $24$.
3. Calculate $28 \div 2$. This equals $14$.

Now, substitute these results back into the expression:

The expression now reads: $24 + 24 - 14$.

Next, perform the addition:

1. Add $24 + 24$. This equals $48$.

Now, subtract $14$ from $48$:

1. Calculate $48 - 14$. This equals $34$.

Thus, after following the order of operations and performing the calculations step-by-step, the final answer is $34$.<|END_OF_LATENT|> The final answer is $34$.