Compute $\sin 270^\circ$.
Rotating the point $(1,0)$ about the origin by $270^\circ$ counterclockwise gives us the point $(0,-1)$, so $\sin 270^\circ = \boxed{-1}$.
-1
Level 2
Geometry
Problem: Compute $\sin 270^\circ$.
Solution:<|START_OF_LATENT|><|PRIOR_PREFIX|>To compute $\sin 270^\circ$, it is important to understand the unit circle, where angles are measured from the positive x-axis. The angle $270^\circ$ corresponds to a point on the unit circle located at the negative y-axis. 

In the unit circle, the coordinates of any point can be expressed as $(\cos \theta, \sin \theta)$ for an angle $\theta$. For $270^\circ$, the coordinates are $(0, -1)$. 

Thus, the sine of the angle is given by the y-coordinate of this point. Therefore, $\sin 270^\circ = -1$. 

This leads to the conclusion that the final answer is $-1$.<|END_OF_LATENT|> The final answer is $-1$.