A toy store manager received a large order of Mr. Slinkums just in time for the holidays. The manager places $20\%$ of them on the shelves, leaving the other 120 Mr. Slinkums in storage. How many Mr. Slinkums were in this order?
If $20\%$ of the toys were put on the shelves, the $80\%$ of the toys were left in storage.  Therefore, we are given $80\% T=120$, where $T$ is the number of toys in the order.  Rewriting $80\%$ as $\frac{4}{5}$ and multiplying both sides by $\frac{5}{4}$, we find that $T=120\cdot\frac{5}{4}=30\cdot 5=\boxed{150}$.
150
Level 3
Prealgebra
Problem: A toy store manager received a large order of Mr. Slinkums just in time for the holidays. The manager places $20\%$ of them on the shelves, leaving the other 120 Mr. Slinkums in storage. How many Mr. Slinkums were in this order?
Solution:<|START_OF_LATENT|><|PRIOR_PREFIX|>Let the total number of Mr. Slinkums in the order be represented by the variable x. The problem states that 20% of the total order is placed on the shelves. This means that the number of Mr. Slinkums placed on the shelves is 0.2x. 

The problem also indicates that the remaining Mr. Slinkums in storage is 120. Therefore, the number of Mr. Slinkums not placed on the shelves can be expressed as the total order minus the number placed on the shelves, which is x - 0.2x. 

This simplifies to 0.8x. According to the information given, this quantity equals 120. Thus, we can set up the equation:

0.8x = 120.

To find x, we need to isolate it. We can do this by dividing both sides of the equation by 0.8:

x = 120 / 0.8.

Calculating the right side gives:

x = 150.

Thus, the total number of Mr. Slinkums in the order is 150.<|END_OF_LATENT|> The final answer is $150$.