I take variable $b$, double it, and add four.  I subtract $4b$ from this new expression, and divide the resulting difference by two.  What is my final expression in simplest form?
We first obtain $2 \cdot b + 4$.  Next, we get $2b + 4 - 4b = -2b +4$.  Dividing this by two, we have $\frac{-2b +4}{2} = \frac{-2}{2} b + \frac{4}{2}$.  This yields $\boxed{-b+2}$, or $\boxed{2 - b}$.
2-b
Level 4
Prealgebra
Problem: I take variable $b$, double it, and add four.  I subtract $4b$ from this new expression, and divide the resulting difference by two.  What is my final expression in simplest form?
Solution:<|START_OF_LATENT|><|PRIOR_PREFIX|>To find the final expression, start with the variable b. Doubling b gives 2b. Adding four to this results in the expression 2b + 4. Next, subtract 4b from this expression. The operation can be represented as (2b + 4) - 4b. Simplifying this, combine like terms: 2b - 4b + 4 equals -2b + 4. 

Now, take the resulting expression -2b + 4 and divide it by two. This division can be expressed as (-2b + 4) / 2. Distributing the division across the terms gives -2b/2 + 4/2, which simplifies to -b + 2. 

Rearranging -b + 2 results in 2 - b. Thus, the final expression in its simplest form is 2 - b.<|END_OF_LATENT|> The final answer is $2-b$.