Solve for $r$ in the equation $19-3=2+r$.
First we simplify the left side, which gives $16 = 2+r$.  Subtracting 2 from both sides gives us $r=\boxed{14}$.
14
Level 1
Prealgebra
Problem: Solve for $r$ in the equation $19-3=2+r$.
Solution:<|START_OF_LATENT|><|PRIOR_PREFIX|>To solve for $r$, first simplify the left side of the equation. Calculate $19 - 3$, which equals $16$. This transforms the equation into $16 = 2 + r$. Next, isolate $r$ by subtracting $2$ from both sides of the equation. This gives $16 - 2 = r$. Performing the subtraction results in $14 = r$. Therefore, the final answer is $14$.<|END_OF_LATENT|> The final answer is $14$.