A bag contains 5 red, 6 green, 7 yellow, and 8 blue jelly beans.   A jelly bean is selected at random.  What is the probability that it is blue?
In total, there are $5+6+7+8=26$ jelly beans in the bag.

Since there are 8 blue jelly beans, the probability of selecting a blue jelly bean is  $$\frac{8}{26}=\boxed{\frac{4}{13}}.$$
\frac{4}{13}
Level 2
Prealgebra
Problem: A bag contains 5 red, 6 green, 7 yellow, and 8 blue jelly beans.   A jelly bean is selected at random.  What is the probability that it is blue?
Solution:<|START_OF_LATENT|><|PRIOR_PREFIX|>To find the probability of selecting a blue jelly bean, we first need to determine the total number of jelly beans in the bag. This involves adding the quantities of each color: 5 red + 6 green + 7 yellow + 8 blue. 

Calculating this gives us:
5 + 6 = 11 (red and green)
11 + 7 = 18 (adding yellow)
18 + 8 = 26 (adding blue)

Thus, the total number of jelly beans is 26. 

Next, we identify the number of favorable outcomes for selecting a blue jelly bean, which is 8, as there are 8 blue jelly beans in the bag. 

The probability of an event is calculated using the formula:
Probability = (Number of favorable outcomes) / (Total number of outcomes)

Substituting the values we have:
Probability = 8 / 26

To simplify this fraction, we find the greatest common divisor (GCD) of 8 and 26, which is 2. 

Dividing both the numerator and the denominator by 2 gives:
8 ÷ 2 = 4
26 ÷ 2 = 13

Thus, the simplified probability of selecting a blue jelly bean is 4/13. 

This leads us to the final answer: the probability that a randomly selected jelly bean is blue is 4/13.<|END_OF_LATENT|> The final answer is $\frac{4}{13}$.