In the diagram, the equilateral triangle has a base of $8$ m. What is the perimeter of the triangle? [asy]
size(100);
draw((0,0)--(8,0)--(4,4*sqrt(3))--cycle);
label("8 m",(4,0),S);
draw((4,-.2)--(4,.2));
draw((1.8,3.5)--(2.2,3.3));
draw((6.3,3.5)--(5.8,3.3));
[/asy]
Since the triangle is equilateral, all sides are equal in length. Therefore, the perimeter of the triangle is $8+8+8=8 \times 3=\boxed{24}.$
24
Level 1
Prealgebra
Problem: In the diagram, the equilateral triangle has a base of $8$ m. What is the perimeter of the triangle? [asy]
size(100);
draw((0,0)--(8,0)--(4,4*sqrt(3))--cycle);
label("8 m",(4,0),S);
draw((4,-.2)--(4,.2));
draw((1.8,3.5)--(2.2,3.3));
draw((6.3,3.5)--(5.8,3.3));
[/asy]
Solution:<|START_OF_LATENT|><|PRIOR_PREFIX|>To find the perimeter of an equilateral triangle, we need to understand that all three sides of the triangle are equal in length. Given that the base of the triangle is 8 m, we can deduce that each side of the triangle measures 8 m. 

The formula for the perimeter \( P \) of a triangle is the sum of the lengths of all its sides. For an equilateral triangle, this can be expressed as:

P = side_1 + side_2 + side_3

Since all sides are equal in an equilateral triangle, we can simplify this to:

P = 3 × side

Substituting the length of one side (which is 8 m) into the equation gives:

P = 3 × 8 m

Calculating this yields:

P = 24 m

Thus, the perimeter of the triangle is 24 m. The final answer is 24.<|END_OF_LATENT|> The final answer is $24$.