timarni/aquarat_alpaca · Datasets at Hugging Face

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there are 8 hours in between 9 a.m. to 5 p.m. 8*5=40 minutes. ANSWER:D	A clock shows the time as 9 a.m. If the minute hand gains 5 minutes every hour, how many minutes will the clock gain by 5 p.m.?	A. 30 min B. 35 min C. 45 min D. 40 min E. 55 min	D. 40 min	aquarat_100	deepmind/aqua_rat
Percent change = (New Value- Old Value )/ old value x 100 =((78-72)/72)x100 = (6/72)*100 = 8.33% There was an 8.33% increase in the cost of item answer -C = 8.33%	At a Supermarket a certain item has increased from 72 cents per pound to 78 cents per pound. What is the % increase in the cost of item?	A. 6.33% B. 7.22% C. 8.33% D. 8% E. 7%	C. 8.33%	aquarat_101	deepmind/aqua_rat
We are looking at numbers between 10000 and 99999 both inclusive. There are 90000 numbers. Now for 10000 : sum of digits is odd; 10001 :sum of digits is even; 10002 : sum of digits is odd ; so on and so forth. So every alternate number is such that the sum of digit is odd. (Exception for the above statement : When it is 10009 the E sum is even and for 10010 again the sum is even; But if you look at 10019 :sum is odd; 10020 : sum is odd and this pattern continues so basically the number of odd sum of digits and even sum of digits are equal) This means exactly half of the numbers will have odd sum of their digits. i.e 45000 Answer :D	How many positive 5-digit integers have the odd sum E of their digits?	A. 910^2 B. 910^3 C. 10^4 D. 4510^3 E. 910^4	D. 45*10^3	aquarat_102	deepmind/aqua_rat
Maximum points of intersection between n different circles = n(n - 1) = 1514 = 210 Answer: E	There are different 15 circles. What is the number of the greatest possible points with which the circles intersect?	A. 390 B. 100 C. 110 D. 180 E. 210	E. 210	aquarat_103	deepmind/aqua_rat
1/9 + 1/10 = 19/90 90/19 = 4.73 days ANSWER: B	B completes a work in 9 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days?	A. 3.75 days B. 4.73 days C. 5.75 days D. 6.75 days E. 7.73 days	B. 4.73 days	aquarat_104	deepmind/aqua_rat
Explanation: Suppose the vessel initially contains 8 litres of liquid. Let x litres of this liquid be replaced with water. Quantity of water in new mixture =(3-3x/8+x)litres Quantity of syrup in new mixture =(5-5x/8)litres (3 - 3x/8 +x)=(5 - 5x/8) =>5x + 24 = 40 - 5x =>10x = 16 =>x = 8/5 So, part of the mixture replaced =(8/5 x 1/8)=1/5. ANSWER IS C	A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?	A. 1/3 B. 1/4 C. 1/5 D. 1/7 E. 1/8	C. 1/5	aquarat_105	deepmind/aqua_rat
Speed = 96kmph = 965/18 = 27 m/s Distance covered in 14sec = 2714 = 378m Answer is A	A car is running at a speed of 96kmph. What distance will it cover in 14sec?	A. 378m B. 350m C. 380m D. 200m E. 250m	A. 378m	aquarat_106	deepmind/aqua_rat
Let seventh observation = X. Then, according to the question we have => (66 + X) / 7 = 10 => X = 4. Hence, the seventh observation is 4. ANSWER:A	The average of 6 observations is 11. A new observation is included and the new average is decreased by 1. The seventh observation is?	A. 4 B. 3 C. 5 D. 6 E. 7	A. 4	aquarat_107	deepmind/aqua_rat
Solution Increase in 10 year= (262500 - 175000) = 87500. Increase% =( f87500/175000x 100 )% = 50% ∴ Required average = ( 50/10 )% = 5% Answer B	The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is :	A. 4.37% B. 5% C. 6% D. 8.75% E. None of these	B. 5%	aquarat_108	deepmind/aqua_rat
plugging numbers is quite fast in this case: Let a=1 b=2 Then; y= 1+2=> 3 and z= 1-2=> -1 Question asks 3ab=......... As our number 3ab= 312=6 now plug the value of y and z in the answer choices. Option A gives 6 and that is the number we need. Hence: Ans is A.	If a + b = y and a - b = z , then 3ab = can someone explain!	A. (3y^2 - 3z^2)/4 B. (3z^2 - 3y^2)/4 C. 3y+3z/2 D. 3y - 3z/2 E. 3y^2 - 3z^2/2	A. (3y^2 - 3z^2)/4	aquarat_109	deepmind/aqua_rat
2:3 2x + 10 : 3x + 10 = 3 : 4 4[2x + 10] = 3[3x + 10] 8x + 40 = 9x + 30 9x - 8x = 40 - 30 x = 10 Then smallest number is = 2 2x = 20 C	If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?	A. 12 B. 18 C. 20 D. 24 E. 26	C. 20	aquarat_110	deepmind/aqua_rat
Let ‘x’ be the average score after 12 th innings ⇒ 12x = 11 × (x – 2) + 65 ∴ x = 43 Answer B	A batsman in his 12th innings makes a score of 65 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’?	A. 42 B. 43 C. 44 D. 45 E. 46	B. 43	aquarat_111	deepmind/aqua_rat
Divisor = (6 * 3) + 7 = 25 5 * Quotient = 25 Quotient = 5. Dividend = (Divisor * Quotient) + Remainder Dividend = (20 * 5) + 6 = 106. E)	In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 7 to the thrice of the remainder. The dividend is	A. 74 B. 78 C. 86 D. 92 E. 106	E. 106	aquarat_112	deepmind/aqua_rat
Total weight increased = (8 x 2.5) kg = 20 kg. Weight of new person = (55 + 20) kg = 75 kg. B)	The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person?	A. 70kg B. 75kg C. 80kg D. 85kg E. 90kg	B. 75kg	aquarat_113	deepmind/aqua_rat
Explanation: Amy can travel clockwise or anticlockwise on the diagram. Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes. Similarly, anticlockwise she has four different routes. Total routes = 8 Answer: B	Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?	A. 10 B. 8 C. 6 D. 4 E. 2	B. 8	aquarat_114	deepmind/aqua_rat
Let the incomes of two companies A and B be 5x and 8x respectively. From the question, 5x+25/8x=5/4 ⇒ 20x + 100 = 40x ∴ x = 5 ∴ Income of company B = 8x = 40 lakh Answer C	Incomes of two companies A and B are in the ratio of 5 : 8. Had the income of company A been more by 25 lakh, the ratio of their incomes would have been 5 : 4. What is the income of company B?	A. 80 lakh B. 50 lakh C. 40 lakh D. 60 lakh E. None of these	C. 40 lakh	aquarat_115	deepmind/aqua_rat
S = (1 + 2 + 3)/2 = 3 => No triangle exists Answer: A	The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.	A. 0 sq m B. 2 sq m C. 9 sq m D. 20 sq m E. 5 sq m	A. 0 sq m	aquarat_116	deepmind/aqua_rat
P:Q = 85000 : 30000 = 17:6. Answer: A	P and Q started a business investing Rs. 85,000 and Rs. 30,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively?	A. 17:6 B. 17:0 C. 17:4 D. 17:2 E. 17:3	A. 17:6	aquarat_117	deepmind/aqua_rat
Explanation : Each of the number can be written as a multiple of 111. And, The factors of 111 are 3 and 37. Thus, the desired answer is 3, 37 and 111. Answer : B	A and B are playing mathematical puzzles. A asks B "which whole numbers, greater than one, can divide all the nine three digit numbers 111,222,333,444,555,666, 777,888 and 999?" B immediately gave the desired answer. It was :-	A. 3, 37 and 119 B. 3, 37 and 111 C. 9, 37 and 111 D. 3, 9 and 37 E. None	B. 3, 37 and 111	aquarat_118	deepmind/aqua_rat
L = S*T S= 1200/120 S= 10 m/Sec. Total length (D)= 1900 m T = D/S T = 1900/10 T = 190 Sec Answer:B	A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?	A. 277 Sec B. 190 Sec C. 187 Sec D. 286 Sec E. 215 Sec	B. 190 Sec	aquarat_119	deepmind/aqua_rat
ARMOUR = 6 letter whereas R repeated twice 6! 6xSx4x3x2x1 => 360 E	In how many different ways can the letters of the word ‘ARMOUM’ be arranged?	A. 200 B. 210 C. 230 D. 250 E. 360	E. 360	aquarat_120	deepmind/aqua_rat
Explanation : Since the given number is divisible by 5, so 0 or 5 must come in place of #. But, a number ending with 5 is never divisible by 8. So, 0 will replace #. Now, the number formed by the last three digits is 4@0, which becomes divisible by 8, if @ is replaced by 4. Hence, digits in place of @ and # are 4 and 0 respectively. Answer : A	Which digits should come in place of @ and # if the number 62684@# is divisible by both 8 and 5?	A. 4,0 B. 0,4 C. 4,4 D. 0,0 E. None	A. 4,0	aquarat_121	deepmind/aqua_rat
Speed of the train relative to man = 125/10 = 25/2 m/sec. = 25/2 * 18/5 = 45 km/hr Let the speed of the train be x km/hr. Then, relative speed = (x - 1) km/hr. x - 1 = 45 => x = 46 km/hr. Answer: E	A train 125 m long passes a man, running at 1 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?	A. 65 km/hr B. 17 km/hr C. 76 km/hr D. 50 km/hr E. 46 km/hr	E. 46 km/hr	aquarat_122	deepmind/aqua_rat
x ------- 8 (x + 10) ---- 6 x * 8 = (x + 10)6 x = 30 \Answer: B	A work which could be finished in 8 days was finished 3 days earlier after 10 more men joined. The number of men employed was?	A. 22 B. 30 C. 88 D. 71 E. 11	B. 30	aquarat_123	deepmind/aqua_rat
let the number be x, now x is halved => x/2..the question asks what is x? x(number) + x/2 (half of that number) = something => 3x/2 = something => x = 2 (something) / 3 so the answer choice must be divisible by 3 eliminate C, E right away check the rest B satisfies 3x/ 2 = 159 => x = 106 Verify. 106 + 53 = 159 Answer is B	Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H	A. 153 B. 159 C. 137 D. 121 E. 89	B. 159	aquarat_124	deepmind/aqua_rat
Let the numbers 13a and 13b. Then, 13a x 13b = 2028 =>ab = 12. Now, the co-primes with product 12 are (1, 12) and (3, 4). [Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ] So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4). Clearly, there are 2 such pairs. Answer: B	The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:	A. 9 B. 2 C. 7 D. 8 E. 1	B. 2	aquarat_125	deepmind/aqua_rat
Renuâ€™s one dayâ€™s work = 1/8 Sumaâ€™s one dayâ€™s work = 1/4 - 1/8 = 1/8 Suma can do it alone in 8 days. ANSWER:A	Renu can do a piece of work in 8 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone?	A. 8 B. 12 C. 14 D. 15 E. 17	A. 8	aquarat_126	deepmind/aqua_rat
Expl : Time taken to carry 2nd person = 300/50 = 6 hrs. Time taken to meet 3rd person =(300-6*10)/(50+10) = 4 hrs Time taken to carry 3rd person = 4 hours Time taken to meet 4th person = (300 –140)/60 = 8/3 Total time = 6+4+4+8/3+8/3 = 58/3 hours Answer :D	There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the stretch while the other two keep running. Then he comes back without wasting time and picks up another person from the way, drives him across the stretch, and does the same for the last person. How long does this whole process take?	A. 24 hrs B. 16 hrs C. 56/3 hrs D. 58/3 hrs E. 18 hrs	D. 58/3 hrs	aquarat_127	deepmind/aqua_rat
X-X-X-X-X --> there are 5 odd digits from 1 to 9, inclusive thus options for the first and the last X's are: 5-X-X-X-X-4. Other X's can take following values: 5-7-6-5-4-4 -> 57654*4=16800. Answer: E.	The security gate at a storage facility requires a Six-digit lock code. If the lock code must consist only of digits from 1 through 9, inclusive, with no repeated digits, and the first and last digits of the code must be odd, how many lock codes are possible?	A. 120 B. 240 C. 360 D. 720 E. 16800	E. 16800	aquarat_128	deepmind/aqua_rat
Sol. CP - = EC7 = 70 1-7 6 77-70 % Profit = 100 = 10% B	If by selling an article for Rs.60, a person loses 1/7 of money, what would he have gained or lost % by selling it for Rs.77?	A. 5% B. 10% C. 20% D. 30% E. 45%	B. 10%	aquarat_129	deepmind/aqua_rat
There are 60 minutes in an hour. In ¾ of an hour there are (60 * ¾) minutes = 45 minutes. In ¾ of an hour there are (60 * 45) seconds = 2700 seconds. Light flashed for every 6 seconds. In 2700 seconds 2700/6 = 450 times. The count start after the first flash, the light will flashes 451 times in ¾ of an hour. Answer:A	If a light flashes every 6 seconds, how many times will it flash in ¾ of an hour?	A. 451 times B. 638 times C. 838 times D. 436 times E. 435 times	A. 451 times	aquarat_130	deepmind/aqua_rat
Answer: CIt may be tempting to come up with a lot of variables, one each for each month's revenue for each company. However, focus on the differences. In the first month, the difference was +40 in favor of A. (Note that we can drop the thousands since every number in the question is in terms of thousands.) In the second, the difference was +6 in favor of A. The average was +2 in favor of A. With these numbers, use the average formula to find the third month (T): (40 + 6 + T)/3 = 2 46 + T = 6 T = -40 Since positive numbers indicate a difference in favor of A, negative numbers are in favor of B. -40 represents a $40,000 advantage in favor of Store B. Choice (B) is correct.	Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $40,000 higher than Store B's revenues. In the second month, Store A's revenues were $6,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?	A. $14,000 B. $40,000 C. $42,000 D. $46,000 E. $50,000	B. $40,000	aquarat_131	deepmind/aqua_rat
( 665432)/(2! 2!*2!)= 540 ways ANSWER:B	some digits were given like 0 2 2 3 3 4 4 then how many no will be there which is greater than 1 lac ,all numbers are distinct	A. 530 B. 540 C. 550 D. 560 E. 570	B. 540	aquarat_132	deepmind/aqua_rat
1 year = Rs. (854 - 815) = Rs. 39. 3 years = Rs.(39 x 3) = Rs. 117. Principal = Rs. (815 - 117) = Rs. 698 ANSWER B	A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:	A. 600 B. 698 C. 675 D. 688 E. 900	B. 698	aquarat_133	deepmind/aqua_rat
If we put a= 1 then A. 2 B. 2 C. -4 E. -3 D. -3=-4 Not true	Each of the following equations has at least one solution EXCEPT D. Is it true?	A. -2-a = 2a B. 2a = (–2)-a C. -4a = -3-a D. -3*a = -3-a E. (–2)-a = –2-a	D. -3*a = -3-a	aquarat_134	deepmind/aqua_rat
Solution: Let average expenditure of 10 people be x. then, 10x = 205+5(x+4); Or, 10x = 205+5x+20; Or, x = 24; So, total money spent = 2410 = Rs. 240. Answer: Option D	10 people went to a hotel for combine dinner party 5 of them spent Rs. 20 each on their dinner and rest spent 4 more than the average expenditure of all the 10. What was the total money spent by them.	A. 1628.4 B. 1534 C. 1492 D. 240 E. None of these	D. 240	aquarat_135	deepmind/aqua_rat
It basically asks for the number of 5s in 150! 150/5 + 150/25 + 150/125 = 30 + 6 + 1. Hence 37 Answer: D.	If x is the product of the integers from 1 to 150, inclusive, and 5^y is a factor of x, what is the greatest possible value of y ?	A. 30 B. 34 C. 36 D. 37 E. 39	D. 37	aquarat_136	deepmind/aqua_rat
The final product is obtained by mixing 864 units of product M with water. In 864 units of Product M, amount of B = 864×77/108 = 616 In the final mixture, concentration of B is 50%. Therefore, the total quantity of final mixture = 616 × 2 = 1232 Water added = 1232 – 864 = 368 The correct answer is Choice B.	Product M is produced by mixing chemical X and chemical Y in the ratio of 5 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M?	A. 328 units B. 368 units C. 392 units D. 616 units E. None of the above	B. 368 units	aquarat_137	deepmind/aqua_rat
Possible scenarios are: 1. Gold/Silver/Bronze/No medal (no ties) - 4!=24; 2. Gold/Gold/Silver/No medal - 4!/2!=12; 3. Gold/Silver/Silver/No medal - 4!/2!=12; 4. Gold/Gold/Gold/No medal - 4!/3!=4. Total Z: 24+12+12+4=52 Answer: B.	In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many Z different victory circles are possible?	A. 24 B. 52 C. 96 D. 144 E. 648	B. 52	aquarat_138	deepmind/aqua_rat
If X can complete a work in x days and Y can complete the same work in y days, then, both of them together can complete the work in x y/ x+ y days Therefore, here, the required number of days = 20Ã— 30/ 50 = 12 days. B)	X completes a work in 20 days and Y complete the same work in 30 days. If both of them work together, then the number of days required to complete the work will be?	A. 10 days. B. 12 days. C. 14 days. D. 8 days. E. 20 days.	B. 12 days.	aquarat_139	deepmind/aqua_rat
Formula = (Selling price ~ Cost price)/Cost price * 100 = (450- 300)/300= 40% gain B	A chair is bought for Rs.300/- and sold at Rs.420/- find gain or loss percentage	A. 15% loss B. 40% gain C. 25% gain D. 30% gain E. 35% gain	B. 40% gain	aquarat_140	deepmind/aqua_rat
The numbers less than 696 and are squares of certain numbers are 676, 625. The least number that should be subtracted from 696 to make it perfect square = 696 - 676 = 20. ANSWER:C	What is the least number to be subtracted from 696 to make it a perfect square?	A. 1 B. 16 C. 20 D. 71 E. 60	C. 20	aquarat_141	deepmind/aqua_rat
approach 1 at-least 1 paper back = total - no paper back 8c3-6c3 = 36 approach 2 at-least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back = 2c16c2+2c26c1 = 36 Answer is C	There are 8 books on a shelf, of which 2 are paperbacks and 6 are hardbacks. How many possible selections of 3 books from this shelf include at least one paperback?	A. a) 40 B. b) 45 C. c) 36 D. d) 55 E. e) 60	C. c) 36	aquarat_142	deepmind/aqua_rat
Explanation: Let sum = x then Simple Interest = x Rate = (100 * x) / (x * 20) = 5 Option D	If a sum of money doubles itself in 20 years at simple interest, the ratepercent per annum is	A. 12 B. 12.5 C. 13 D. 5 E. 14	D. 5	aquarat_143	deepmind/aqua_rat
Total cars=4 1.154=4.6->Service Cost Fuel Cost in Sports Car = 2320.4=25.6 Fuel Cost in Executive Car=25.67/4=44.8 Total Fuel Cost = 25.6+44.8=70.4 Cost to fuel car = 70.4+4.6=75 Answer: B	In a fuel station the service costs $1.15 per car, every liter of fuel costs 0.4$. Assuming that you own 2 sports cars and 2 executive cars and all fuel tanks are empty. How much will it cost to fuel all cars together if a sports car tank is 32 liters and an executive car tank is 75% bigger?	A. 37.5$ B. 75$ C. 87.5$ D. 94.5$ E. 98.4$	B. 75$	aquarat_144	deepmind/aqua_rat
C EV The first letter moves one step forward. The second letter moves one step backward. Answer is C	Choose the missing terms out of the given alternatives. AZ, BY, CX, DW ?	A. EF B. GH C. EV D. DW E. KN	C. EV	aquarat_145	deepmind/aqua_rat
Total revenues = x Spent on marketing = x/4 Remaining amount = x-x/4 = 3x/4 1/7 of the remainder on maintenance of its facilities = 3x/4*1/7 = 3x/28 Amount left = 3x/4-3x/28 = 9x/14 Answer D	Company Z spent 1/4 of its revenues last year on marketing and 1/7 of the remainder on maintenance of its facilities. What fraction of last year’s original revenues did company Z have left after its marketing and maintenance expenditures?	A. 5/14 B. 1/2 C. 17/28 D. 9/14 E. 9/11	D. 9/14	aquarat_146	deepmind/aqua_rat
Speed = 45 * 5/18 = 25/2 m/sec Total distance covered = 360 + 140 = 500 m Required time = 500 * 2/25 = 40 sec ANSWER:A	A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?	A. 40 sec B. 42 sec C. 45 sec D. 48 sec E. 58 sec	A. 40 sec	aquarat_147	deepmind/aqua_rat
For Maximum value : It should be less than 1/21 + 1/21 +1/21... 10 times = 10/21 ~ 1/2 For Minimum Value : It should be greater than 1/30+ 1/30+ 1/30 .. 10 times = 10/30 = 1/3 Thus, the answer should lie between 1/3 and 1/2. Correct ans : D.	What is the scope including 1/21+1/22+1/23+......+1/30?	A. 1/6~1/5 B. 1/5~1/4 C. 1/4~1/3 D. 1/3~1/2 E. 1/2~1	D. 1/3~1/2	aquarat_148	deepmind/aqua_rat
Looks easy: -- 9C4*5C1 + 9C5= 756 (E).	Company A has 13 employees, 9 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?	A. 56 B. 231 C. 336 D. 350 E. 756	E. 756	aquarat_149	deepmind/aqua_rat
Total number of balls = 5+2 = 7 n(S) = 7C3 = 765 / 32 = 35 n(E) = 2C2 5C1 = 5 Probability = 5/35 = 1/7 Answer is A	A bag contains 5 red, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls?	A. 1/7 B. 2/9 C. 3/11 D. 4/17 E. 2/3	A. 1/7	aquarat_150	deepmind/aqua_rat
0.5x/21 + 0.5x/24 = 20 --> x/21 + x/24 = 40 --> x =448 km. D	A woman complete a journey in 20 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.	A. 334 km. B. 216 km. C. 314 km. D. 448 km. E. 544 km.	D. 448 km.	aquarat_151	deepmind/aqua_rat
Denote X as the sum of the heights of the two new people. From the stem it follows that (700+X)6>175. This reduces to X>350. Only the heights from B add up to 350 cm. All other pairs add up to more than 350 cm. Answer: B	The average height in a group of 4 people is 175 cm. If the average height increased when 2 more people were added to the group, which of the following cannot be the heights of the two new people?	A. 179 cm and 172 cm B. 181 cm and 169 cm C. 173 cm and 178 cm D. 176 cm and 176 cm E. 174 cm and 177 cm	B. 181 cm and 169 cm	aquarat_152	deepmind/aqua_rat
A+B=60 A=2B 2B+B=60===>B=20 A=40 5 yrs ages 45 and 25 Sum of their ages = 70 ANSWER A	The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?	A. 70 B. 55 C. 60 D. 65 E. 80	A. 70	aquarat_153	deepmind/aqua_rat
Let the number be x. Then, 15x - x = 196 <=> 14x = 196 <=> x = 14. Answer :A	Find the number which when multiplied by 15 is increased by 196.	A. 14 B. 20 C. 26 D. 28 E. 30	A. 14	aquarat_154	deepmind/aqua_rat
Average of 5, 7, 14 and Y = ( 5 + 7 + 14 + Y )/ 4 Therefore, X = 80% of ( 5 + 7 + 14 + y )/ 4 = (80/100) x (26 + Y)/4 => X = (26 + Y)/5 5X - Y = 26----- (i) Also, (X + Y)/2 = 26 ----- (ii) From (i)and (ii) X = 13 Y = 39. ANSWER:C	A number X equals 80% of the average of 5, 7, 14 and a number Y. If the average of X and Y is 26, the value of Y is?	A. 13 B. 26 C. 39 D. 36 E. None of these	C. 39	aquarat_155	deepmind/aqua_rat
Let distance = x m Usual rate = y kmph x/y – x/y+3 = 40/60 hr 2y(y+3) = 9x ---------------------------------(1) x/y-2 – x/y = 40/60 hr y(y-2) = 3x -----------(2) divide 1 & 2 equations by solving we get x = 40 km Answer : B	A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is.	A. 30 km B. 40 km C. 45 km D. 50 km E. 55 km	B. 40 km	aquarat_156	deepmind/aqua_rat
Number plugging in will be best strategy for this question. Let p = 5%, Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence D is the correct answer.	The number of livestock in a farm at the beginning of year 2000 was 130,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 130,000. Which of the following expressions is correct?	A. With the exception of 1 instance, p will be equal to q B. q > p C. p = q D. p > q E. There is no relation between p and q	D. p > q	aquarat_157	deepmind/aqua_rat
Explanation: 3 men reap 1/10 field in 1 day 1 man reap 1/(3 x 10) 4 women reap 1/10 field in 1 day 1 woman reap 1/(10 x 4) 5 men and 6 women reap (5/(3 x 10)+ 6/(4 x 10)) =19/60 in 1 day 5 men and 6 women will reap the field in 19/60 days Answer: Option A	If 3 men or 4 women can reap a field in 10 days how long will 5 men and 6 women take to reap it?	A. 19/60 B. 9/60 C. 2/3 D. 5/18 E. 6/24	A. 19/60	aquarat_158	deepmind/aqua_rat
15^n = 5^n * 3^n Highest prime factor will be the limiting factor. 100/5 +100/25 =20+4 = 24 ANSWER:E	What is the greatest possible value of integer n if 100! is divisible by 15^n	A. 20 B. 21 C. 22 D. 23 E. 24	E. 24	aquarat_159	deepmind/aqua_rat
2nd term = (1st term) * 1 + 1 = 15 1 + 1 = 16. 3rd term = (2nd term) 2 + 2 = 16 * 2 + 2 = 34 4th term = (3th term) 3 + 3 = 34 3 + 3 = 105 5th term = (4th term) * 4 + 4 = 105 * 4 + 4 = 424 6th term = (5th term) * 5 + 5 = 424 * 5 + 5 = 2125 6th term should 2125 instead of 2124. E	Find the invalid no.from the following series 15, 16, 34, 105, 424, 2124, 12756	A. 15 B. 16 C. 34 D. 105 E. 2124	E. 2124	aquarat_160	deepmind/aqua_rat
To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/4 > 1/5. The greatest multiple of 4 less than 45 is 40 (such that the remaining number is divisible by 5), so let's assume there were 40 dogs and 5 cats. Then the maximum number of adopted pets is 1/4(40) + 1/5(5) = 10 + 1 = 11. The answer is B.	On Monday, a certain animal shelter housed 45 cats and dogs. By Friday, 1/5 of the cats and 1/4 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?	A. 10 B. 11 C. 12 D. 13 E. 14	B. 11	aquarat_161	deepmind/aqua_rat
Original price = 1120 × 100⁄70 × 100⁄80 = 2000 Answer D	A shopkeeper gave an additional 20 per cent concession on the reduced price after giving 30 per cent standard concession on an article. If Arun bought that article for 1,120, what was the original price?	A. 3,000 B. 4,000 C. 2,400 D. 2,000 E. None of these	D. 2,000	aquarat_162	deepmind/aqua_rat
(A+B)-(B-C)=10 A-C=10 Answer is C	The total age of A and B is 10 years more than the total age of B and C. C is how many years younger than A.?	A. 16 B. 12 C. 10 D. 20 E. 10	C. 10	aquarat_163	deepmind/aqua_rat
100 % - 10 % = 90 % 54%-36%=18% 18% ------> 3600 ( 18 × 200 = 3600) 100% -------> 20000 votes (100 × 200 = 20000) C	In an election between two candidates, 10% of votes are were declares invalid. First candidate got 3600 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:	A. 9000 B. 98000 C. 20000 D. 11000 E. 12000	C. 20000	aquarat_164	deepmind/aqua_rat
A The number is: 12345679 12345679 * 9 = 111111111 12345679 * 18 = 222222222 12345679 * 27 = 333333333 And so on...	Find a 8 digit number that if multiplied by the number 9 or any of its multiplications products (18, 27, 36, 45,..) will result in the multiplication factor repeated (n) number of times.	A. 12345679 B. 42345675 C. 22347379 D. 52345673 E. 21345679	A. 12345679	aquarat_165	deepmind/aqua_rat
(36 + 66): (7*12) 54:84 => 9:14.Answer:C	A and B invests Rs.3000 and Rs.7000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?	A. 9:6 B. 9:8 C. 9:14 D. 9:9 E. 9:5	C. 9:14	aquarat_166	deepmind/aqua_rat
Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80*(20/100) = Rs. 96 Present Savings = 100 – 96 =Rs. 4 100 ------ 4 ? --------- 200 => 5000 Answer: A	A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?	A. 5000 B. 2889 C. 2779 D. 6257 E. 5362	A. 5000	aquarat_167	deepmind/aqua_rat
Let the speed of the water in still water =x Given that speed of the stream = 3 kmph Speed downstream =(x+3) kmph Speed upstream =(xâˆ’3) kmph He travels a certain distance downstream in 1 hour and come back in 11â„2 hour. i.e., distance travelled downstream in 1 hour = distance travelled upstream in 11â„2 hour Since distance = speed Ã— time, we have (x+3)Ã—1=(x-3)3/2 2(x+3)=3(x-3) 2x+6=3x-9 x=6+9=15 kmph Answer: D	A boat covers a certain distance downstream in 1 hour, while it comes back in 11â„2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?	A. 31 kmph B. 16 kmph C. 19 kmph D. 15 kmph E. 14 kmph	D. 15 kmph	aquarat_168	deepmind/aqua_rat
A : B (40004)+(10008) : (60008)+(30004) 24000 : 60000 2 : 5 Answer: A	A and B invests Rs.4000 and Rs.6000 in a business. After 4 months, A withdraws three-fourth of his capital and 4 months later, B withdraws half of his capital. In what ratio should they share the profits at the end of the year?	A. 2:5 B. 3:5 C. 4:5 D. 3:7 E. 5:7	A. 2:5	aquarat_169	deepmind/aqua_rat
The pattern is + 0.05, + 0.10, + 0.15, ..... Answer : D.	0.5, 0.55, 0.65, 0.8, ?	A. 0.7 B. 0.9 C. 0.95 D. 1 E. 2	D. 1	aquarat_170	deepmind/aqua_rat
15 W = 10 M Now, 5W + 4M = 5W + 4×15/10W = 5W + 6W = = 11 W If 15 women can complete the project in 55 days, 11 women can complete the same project in 55×15/11=75days Answer A	If 15 women or 10 men can complete a project in 55 days, in how many days will 5 women and 4 men working together complete the same project ?	A. 75 B. 8 C. 9 D. 85 E. None of these	A. 75	aquarat_171	deepmind/aqua_rat
450 = 2 * 3^2 * 5^2 If 450 divides n^2, then n must be divisible by 2 * 3 * 5 = 30 The answer is C.	If n is a positive integer and n^2 is divisible by 450, then what is the largest positive integer that must divide n?	A. 10 B. 20 C. 30 D. 40 E. 50	C. 30	aquarat_172	deepmind/aqua_rat
1/10 + 1/15 = 1/6 * 4 = 2/3 1 - 2/3 = 1/3 1/10 + 1/15 - 1/x = 1/3 x = 8 Answer:B	Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?	A. 6 B. 8 C. 7 D. 4 E. 1	B. 8	aquarat_173	deepmind/aqua_rat
Each member out of 14, including Harry, has equal chances to be selected for any of the positions (the sequence of the selection is given just to confuse us). The probability that Harry will be selected to be the secretary is 1/14 and the probability that Harry will be selected to be the treasurer is also 1/14. So, the probability that Harry will be selected to be either the secretary or the the treasurer is 1/14+1/14=2/14. Answer: D.	A certain club has 14 members, including Harry. One of the 14 members is to be chosen at random to be the president, one of the remaining 13 members is to be chosen at random to be the secretary, and one of the remaining 12 members is to be chosen at random to be the treasurer. What is the probability that Harry will either be the secretary or the member chosen to be the treasurer?	A. 5/7 B. 4/7 C. 3/7 D. 1/7 E. 2/7	D. 1/7	aquarat_174	deepmind/aqua_rat
Explanation: From given details we know that she walks in square shaped path and will be in 1 km away from starting point. ANSWER IS C	Afreena walks 8 km towards East and then walks 13 km back, then she turns left and walks 4 km; then walks 5 km after turning left; she turns left again and walks 3 km. How far is she from the starting point ?	A. 3 km B. 2 km C. 1 km D. 6 km E. 7 km	C. 1 km	aquarat_175	deepmind/aqua_rat
W women and M men..now 4 women and 2 men are added then total women = W+4 and total men = M+2.. if we club both as total one team (W + M + 6) We need to find the probability that the team captain will be a woman => W+4 / (W + M + 6).. IMO option A is correct answer...	A coed soccer team has W women and M men on the team. If 4 women and 2 men are added to the team roster, and if one person on the team is selected at random to serve as team captain, then the probability that the team captain will be a woman can be represented as	A. (W + 4)/(W + M + 6) B. (W + 4)/(W + M + 2) C. (W + 4)/(M + 2) D. (W + 4)/(W + M) E. W/M	A. (W + 4)/(W + M + 6)	aquarat_176	deepmind/aqua_rat
Solution Let the son's present age be x years .Then, man's present age = (x+30)years. Then â€¹=â€º(x+30)+2= 2(x+2) â€¹=â€ºx+32=2x+4 x= 28. Answer B	A man is 30 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is	A. 14 years B. 28 years C. 20 years D. 22 years E. None	B. 28 years	aquarat_177	deepmind/aqua_rat
1 lbs of raisin = $1 3 lbs of raisin = $3 1 lbs of nuts = $3 3 lbs of nuts = $9 Total value of mixture = 9+3 = 12 Fraction of the value of raisin = 3/12 = 1/4 Ans:C	Chris mixed 3 pounds of raisins with 3 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?	A. 1/7 B. 1/5 C. 1/4 D. 1/3 E. 3/7	C. 1/4	aquarat_178	deepmind/aqua_rat
2^(2w) = 8^(w−2) 2^(2w) = 2^(3*(w−2)) 2^(2w) = 2^(3w-6) Let's equate the exponents as the bases are equal. 2w = 3w-6 w = 6 The answer is B.	If 2^(2w) = 8^(w−2), what is the value of w?	A. 3 B. 6 C. 9 D. 12 E. 15	B. 6	aquarat_179	deepmind/aqua_rat
Solution Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours. =170 hours. The watch gains = (2 + 4 x4/5)min = 34 / 5 min.in 170 hrs. Now,34/5 min are gained in 170 hrs. 2 min are gained in(170x 5/34 x2)hrs. Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m.on Wednesday. Answer B	A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?	A. 2 p.m. on Tuesday B. 2 p.m. on Wednesday C. 3 p.m. on Thursday D. 1 p.m. on Friday E. None	B. 2 p.m. on Wednesday	aquarat_180	deepmind/aqua_rat
Let's say the two cars have speeds V1 and V2. The fact that they are moving in opposite direction means that their relative speed is (V1 + V2). In other words, any gap between them will be changing in size at a rate of (V1 + V2). It doesn't matter whether they are moving toward each other or away from each other. If they are approaching each other, the gap between them is decreasing at a rate of (V1 + V2). If they are moving away from each other, the gap between them is increasing at a rate of (V1 + V2). Either way, the number for the rate of change remains the same. Here, the two cars approach a distance 40 mi, then move away from each other another distance of 40 miles. That's a total distance of 80 miles in 1.5 hr, which gives a rate of: R = (80 mi)/(1.5) = 53.33 mph That's the rate of change of the gap, so it must equal the sum of the speeds of the two cars. One of the speeds is x, and let's call the other y. We want y. x + y = 53.33 y = 53.33 - x Answer =(B)	Otto and Han are driving at constant speeds in opposite directions on a straight highway. At a certain time they are driving toward each other and are 40 miles apart. One and a half hours later, they are again 40 miles apart, driving away from each other. If Otto drives at a speed of x miles per hour, then, in terms of x, Han drives at a speed of how many miles per hour?	A. a) 80-x B. b) 53.33-x C. c) 80-2x D. d) 120-x E. e) 40-x/2	B. b) 53.33-x	aquarat_181	deepmind/aqua_rat
theta degree=11/2m-30h =11/2(45)-30(3) =247.5-90 =157.5 or 157 1/2 degree ANSWER:E	The angle between two hands at 3.45 is	A. 110 degree B. 115 degree C. 112 1/2 degree D. 117 degree E. 157 1/2 degree	E. 157 1/2 degree	aquarat_182	deepmind/aqua_rat
Time = 4 Distance = 620 3/2 of 4 hours = 4 * 3/2 = 6 Hours Required speed = 620/6 = 103 Kmph D)	A jeep takes 4 hours to cover a distance of 620 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?	A. 148 Kmph B. 152 Kmph C. 106 Kmph D. 103 Kmph E. 165 Kmph	D. 103 Kmph	aquarat_183	deepmind/aqua_rat
Solution At 8 o'clock, the hour is at 8 and the minute hand is at 12,i.e. the two hands are 20 min. Spaces apart. So, the minute hand gain = (30 - 20)minute 55 minutes will be gained in 60 min. 10 minutes spaces will be gained in (60/55 x10) min. = 10x10/11 min. The hands will be in the same straight line but not together at 10x10/11 min.past 8. Answer B	Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together.	A. 10x11/10 B. 10x10/11 C. 11x10/11 D. 12x10/11 E. None	B. 10x10/11	aquarat_184	deepmind/aqua_rat
If Pugsley were to give Wednesday four of his spiders, Wednesday would then have five times as many spiders as Pugsley does: (w + 4) = 4(p - 4) If Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded: p + 5 = w - 5 Solving gives p = 10 and w = 20. Answer: D.	On Sunday morning, Pugsley and Wednesday are trading pet spiders. If Pugsley were to give Wednesday four of his spiders, Wednesday would then have four times as many spiders as Pugsley does. But, if Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded. How many pet spiders does Pugsley have before the trading game commences?	A. 6 B. 7 C. 8 D. 10 E. 12	D. 10	aquarat_185	deepmind/aqua_rat
6C2 + 6C3 = 15 + 20 = 35 The answer is B.	To apply for the position of photographer at a local magazine, a photographer needs to include two or three photos in an envelope accompanying the application. If the photographer has pre-selected six photos representative of her work, how many choices does she have to provide the photos for the magazine?	A. 32 B. 35 C. 36 D. 40 E. 42	B. 35	aquarat_186	deepmind/aqua_rat
Just to add some more to Bunuel's explanation, if a number is a multiple of 3, it will be in a form: n = 3k, where k is an integer And if a number is a multiple of 6, it will be in a form : m = 6l, where l is an integer so m = 2 * 3 * l = (2l) 3 = 3 * p, where p is an integer. In other words, the prime factorization of m must have 3 as a factor, if it's a multiple of 6, but the expression can't have that (as explained by Bunuel), so it can't be a multiple of 6 either ANSWER:C	If x is an integer and y = 3x + 2, which of the following CANNOT be a divisor of y?	A. 4 B. 5 C. 6 D. 7 E. 8	C. 6	aquarat_187	deepmind/aqua_rat
C.P. = 400W S.P. = 1.8W150 + 1.2W100 + 0.6W150 = 480W Since, S.P. > C.P., there is net profit. Profit = S.P. - C.P. = 480W - 400W = 80W Profit % = (Profit/C.P.)100 = (80W/400W)*100 = 20% So, the correct answer is D.	A book store bought copies of a new book by a popular author, in anticipation of robust sales. The store bought 400 copies from their supplier, each copy at wholesale price W. The store sold the first 150 copies in the first week at 80% more than W, and then over the next month, sold a 100 more at 20% more than W. Finally, to clear shelf space, the store sold the remaining copies to a bargain retailer at 40% less than W. What was the bookstore’s net percent profit or loss on the entire lot of 400 books?	A. 30% loss B. 10% loss C. 10% profit D. 20% profit E. 60% profit	D. 20% profit	aquarat_188	deepmind/aqua_rat
Total no of ways in which you can select a committee of 2 people out of 7 people is 7C2 ways= 21 ways Requirement is at-least 1 preacher= 4C1*3C1+4C2 or 7C2-3C2=18 ways Probability= 18/21 = 6/7 ANSWER:D	A committee of 2 people is to be selected out of 3 teachers and 4 preachers. If the committee is selected at random, what is the probability that the committee will be composed of at least 1 preacher?	A. 1/4 B. 1/3 C. 2/3 D. 6/7 E. 8/9	D. 6/7	aquarat_189	deepmind/aqua_rat
Prime Factoring: you need a 2 and a 5 to make a 10 (a "zero"), and there are TONS of 2's so let's skip these and focus on the (rarer) 5s: 80! = 123456...787980 Since there are 80 consecutive numbers, there are 16 multiples of 5 in there, but if we're prime factoring, we need to remember that SOME multiples of 5 actually contain more than just one 5. Which? 25 comes to mind -- it's got two of them! So all the multiples of 25 actually contain two 5's (ie: 50 and 75) So, to recap, we have 16 of them, plus 3 more (the additional 5's in 25, 50, and 75), so that makes 19, and since we have more than enough 2's, we know our number will have exactly 19 zeros at the end. ANSWER:D	If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end?	A. 16 B. 17 C. 18 D. 19 E. 20	D. 19	aquarat_190	deepmind/aqua_rat
Juan's income = 100 (assume); Tim's income = 60 (40 percent less than Juan's income); Mary's income = 96 (60 percent more than Tim's income). Thus, Mary's income (96) is 96% of Juan's income (100). Answer: C	Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?	A. 124% B. 120% C. 96% D. 80% E. 64%	C. 96%	aquarat_191	deepmind/aqua_rat
They should share the profits in the ratio of their investments. The ratio of the investments made by Y and Z = 3000 : 6000 => 1:2 . Answer:E	Y and Z start a business with Rs.3000 and Rs.6000 respectively. How should they share their profits at the end of one year?	A. 4:1 B. 1:3 C. 1:4 D. 1:5 E. 1:2	E. 1:2	aquarat_192	deepmind/aqua_rat
he answer will be a number which doesn't completely divide 100! No of 5's in 100! = 24 No of 7's in 100! = 16 No of 11's in 100! = 9 No of 13's in 100! = 7 No of 17's in 100! = 5 There are 5 seventeens in 100! , however we are dividing by 17^6 , so this can not divide 100! Hence our answer will be E	If 100!/x is not an integer, which of the following could be the value of x?	A. 5^24 B. 7^16 C. 11^9 D. 13^6 E. 17^6	E. 17^6	aquarat_193	deepmind/aqua_rat
Let age of R =x. Then, Age of Q =2x Age of P =2+2x Total age of P,Q and R =25 ⇒(2+2x)+2x+x=25 ⇒5x=23 ⇒x=23/5=4.6 years B's age =2x=2×4.6=9.2 years ANSWER:D	P is two years older than Q who is twice as old as R. The total of the ages of P, Q and R is 25. How old is Q?	A. 7.2 years B. 8.2 years C. 9.8 years D. 9.2 years E. 9.4 years	D. 9.2 years	aquarat_194	deepmind/aqua_rat
M = 20 S = 7 DS = 20 + 7 = 27 Answer: D	A man can row with a speed of 20 kmph in still water. If the stream flows at 7 kmph, then the speed in downstream is?	A. 27 B. 23 C. 20 D. 27 E. 12	D. 27	aquarat_195	deepmind/aqua_rat
Deviation from the mean for the daytime staff = 75 - 65 = 10. Deviation from the mean for the evening staff = 65 - 60 = 5. Thus, the ratio of the number of daytime staff members to the number of evening staff members is 5:10 = 1:2. The answer is A.	A theater box office sold an average (arithmetic mean) of 65 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 75, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members?	A. 1:2 B. 1:4 C. 5:11 D. 1:3 E. 13:15	A. 1:2	aquarat_196	deepmind/aqua_rat
Let the present ages of Sameer and Anand be 5x years and 4x years respectively. Then, (5x + 4/4x + 4)=11/9 9(5x + 4) = 11(4x + 4) 45x + 36 = 44x + 44 45x - 44x = 44 - 36 x = 8. Anand's present age = 4x = 32 years. Answer:D	Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Four years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?	A. A)24 B. B)89 C. C)67 D. D)32 E. E)45	D. D)32	aquarat_197	deepmind/aqua_rat
18 m/s = 12 * 18/5 kmph 3 hours 45 minutes = 3 3/4 hours = 15/4 hours Distance = speed * time = 18 * 18/5 * 15/4 km = 243 km. Answer: E	If a man can cover 18 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?	A. 288 B. 162 C. 878 D. 168 E. 243	E. 243	aquarat_198	deepmind/aqua_rat
Explanation: Meaningful words are ROSE, SORE and EROS. Note the meaning of the words SORE and EROS with the help of dictionary. Answer: B) Three	How many meaningful English words can be formed with the letters ESRO using each letter only once in each word?	A. 1 B. 3 C. 4 D. 8 E. 9	B. 3	aquarat_199	deepmind/aqua_rat

there are 8 hours in between 9 a.m. to 5 p.m. 8*5=40 minutes. ANSWER:D

A clock shows the time as 9 a.m. If the minute hand gains 5 minutes every hour, how many minutes will the clock gain by 5 p.m.?

A. 30 min B. 35 min C. 45 min D. 40 min E. 55 min

D. 40 min

aquarat_100

deepmind/aqua_rat

Percent change = (New Value- Old Value )/ old value x 100 =((78-72)/72)x100 = (6/72)*100 = 8.33% There was an 8.33% increase in the cost of item answer -C = 8.33%

At a Supermarket a certain item has increased from 72 cents per pound to 78 cents per pound. What is the % increase in the cost of item?

A. 6.33% B. 7.22% C. 8.33% D. 8% E. 7%

C. 8.33%

aquarat_101

deepmind/aqua_rat

We are looking at numbers between 10000 and 99999 both inclusive. There are 90000 numbers. Now for 10000 : sum of digits is odd; 10001 :sum of digits is even; 10002 : sum of digits is odd ; so on and so forth. So every alternate number is such that the sum of digit is odd. (Exception for the above statement : When it is 10009 the E sum is even and for 10010 again the sum is even; But if you look at 10019 :sum is odd; 10020 : sum is odd and this pattern continues so basically the number of odd sum of digits and even sum of digits are equal) This means exactly half of the numbers will have odd sum of their digits. i.e 45000 Answer :D

How many positive 5-digit integers have the odd sum E of their digits?

A. 9*10^2 B. 9*10^3 C. 10^4 D. 45*10^3 E. 9*10^4

D. 45*10^3

aquarat_102

deepmind/aqua_rat

Maximum points of intersection between n different circles = n*(n - 1) = 15*14 = 210 Answer: E

There are different 15 circles. What is the number of the greatest possible points with which the circles intersect?

A. 390 B. 100 C. 110 D. 180 E. 210

E. 210

aquarat_103

deepmind/aqua_rat

1/9 + 1/10 = 19/90 90/19 = 4.73 days ANSWER: B

B completes a work in 9 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days?

A. 3.75 days B. 4.73 days C. 5.75 days D. 6.75 days E. 7.73 days

B. 4.73 days

aquarat_104

deepmind/aqua_rat

Explanation: Suppose the vessel initially contains 8 litres of liquid. Let x litres of this liquid be replaced with water. Quantity of water in new mixture =(3-3x/8+x)litres Quantity of syrup in new mixture =(5-5x/8)litres (3 - 3x/8 +x)=(5 - 5x/8) =>5x + 24 = 40 - 5x =>10x = 16 =>x = 8/5 So, part of the mixture replaced =(8/5 x 1/8)=1/5. ANSWER IS C

A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

A. 1/3 B. 1/4 C. 1/5 D. 1/7 E. 1/8

C. 1/5

aquarat_105

deepmind/aqua_rat

Speed = 96kmph = 96*5/18 = 27 m/s Distance covered in 14sec = 27*14 = 378m Answer is A

A car is running at a speed of 96kmph. What distance will it cover in 14sec?

A. 378m B. 350m C. 380m D. 200m E. 250m

A. 378m

aquarat_106

deepmind/aqua_rat

Let seventh observation = X. Then, according to the question we have => (66 + X) / 7 = 10 => X = 4. Hence, the seventh observation is 4. ANSWER:A

The average of 6 observations is 11. A new observation is included and the new average is decreased by 1. The seventh observation is?

A. 4 B. 3 C. 5 D. 6 E. 7

A. 4

aquarat_107

deepmind/aqua_rat

Solution Increase in 10 year= (262500 - 175000) = 87500. Increase% =( f87500/175000x 100 )% = 50% ∴ Required average = ( 50/10 )% = 5% Answer B

The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is :

A. 4.37% B. 5% C. 6% D. 8.75% E. None of these

B. 5%

aquarat_108

deepmind/aqua_rat

plugging numbers is quite fast in this case: Let a=1 b=2 Then; y= 1+2=> 3 and z= 1-2=> -1 Question asks 3ab=......... As our number 3ab= 3*1*2=6 now plug the value of y and z in the answer choices. Option A gives 6 and that is the number we need. Hence: Ans is A.

If a + b = y and a - b = z , then 3ab = can someone explain!

A. (3y^2 - 3z^2)/4 B. (3z^2 - 3y^2)/4 C. 3y+3z/2 D. 3y - 3z/2 E. 3y^2 - 3z^2/2

A. (3y^2 - 3z^2)/4

aquarat_109

deepmind/aqua_rat

2:3 2x + 10 : 3x + 10 = 3 : 4 4[2x + 10] = 3[3x + 10] 8x + 40 = 9x + 30 9x - 8x = 40 - 30 x = 10 Then smallest number is = 2 2x = 20 C

If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 3:4 then find the smallest number?

A. 12 B. 18 C. 20 D. 24 E. 26

C. 20

aquarat_110

deepmind/aqua_rat

Let ‘x’ be the average score after 12 th innings ⇒ 12x = 11 × (x – 2) + 65 ∴ x = 43 Answer B

A batsman in his 12th innings makes a score of 65 and thereby increases his average by 2 runs. What is his average after the 12th innings if he had never been ‘not out’?

A. 42 B. 43 C. 44 D. 45 E. 46

B. 43

aquarat_111

deepmind/aqua_rat

Divisor = (6 * 3) + 7 = 25 5 * Quotient = 25 Quotient = 5. Dividend = (Divisor * Quotient) + Remainder Dividend = (20 * 5) + 6 = 106. E)

In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 7 to the thrice of the remainder. The dividend is

A. 74 B. 78 C. 86 D. 92 E. 106

E. 106

aquarat_112

deepmind/aqua_rat

Total weight increased = (8 x 2.5) kg = 20 kg. Weight of new person = (55 + 20) kg = 75 kg. B)

The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 55 kg. What might be the weight of the new person?

A. 70kg B. 75kg C. 80kg D. 85kg E. 90kg

B. 75kg

aquarat_113

deepmind/aqua_rat

Explanation: Amy can travel clockwise or anticlockwise on the diagram. Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes. Similarly, anticlockwise she has four different routes. Total routes = 8 Answer: B

Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?

A. 10 B. 8 C. 6 D. 4 E. 2

B. 8

aquarat_114

deepmind/aqua_rat

Let the incomes of two companies A and B be 5x and 8x respectively. From the question, 5x+25/8x=5/4 ⇒ 20x + 100 = 40x ∴ x = 5 ∴ Income of company B = 8x = 40 lakh Answer C

Incomes of two companies A and B are in the ratio of 5 : 8. Had the income of company A been more by 25 lakh, the ratio of their incomes would have been 5 : 4. What is the income of company B?

A. 80 lakh B. 50 lakh C. 40 lakh D. 60 lakh E. None of these

C. 40 lakh

aquarat_115

deepmind/aqua_rat

S = (1 + 2 + 3)/2 = 3 => No triangle exists Answer: A

The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.

A. 0 sq m B. 2 sq m C. 9 sq m D. 20 sq m E. 5 sq m

A. 0 sq m

aquarat_116

deepmind/aqua_rat

P:Q = 85000 : 30000 = 17:6. Answer: A

P and Q started a business investing Rs. 85,000 and Rs. 30,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively?

A. 17:6 B. 17:0 C. 17:4 D. 17:2 E. 17:3

A. 17:6

aquarat_117

deepmind/aqua_rat

Explanation : Each of the number can be written as a multiple of 111. And, The factors of 111 are 3 and 37. Thus, the desired answer is 3, 37 and 111. Answer : B

A and B are playing mathematical puzzles. A asks B "which whole numbers, greater than one, can divide all the nine three digit numbers 111,222,333,444,555,666, 777,888 and 999?" B immediately gave the desired answer. It was :-

A. 3, 37 and 119 B. 3, 37 and 111 C. 9, 37 and 111 D. 3, 9 and 37 E. None

B. 3, 37 and 111

aquarat_118

deepmind/aqua_rat

L = S*T S= 1200/120 S= 10 m/Sec. Total length (D)= 1900 m T = D/S T = 1900/10 T = 190 Sec Answer:B

A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?

A. 277 Sec B. 190 Sec C. 187 Sec D. 286 Sec E. 215 Sec

B. 190 Sec

aquarat_119

deepmind/aqua_rat

ARMOUR = 6 letter whereas R repeated twice 6! 6xSx4x3x2x1 => 360 E

In how many different ways can the letters of the word ‘ARMOUM’ be arranged?

A. 200 B. 210 C. 230 D. 250 E. 360

E. 360

aquarat_120

deepmind/aqua_rat

Explanation : Since the given number is divisible by 5, so 0 or 5 must come in place of #. But, a number ending with 5 is never divisible by 8. So, 0 will replace #. Now, the number formed by the last three digits is 4@0, which becomes divisible by 8, if @ is replaced by 4. Hence, digits in place of @ and # are 4 and 0 respectively. Answer : A

Which digits should come in place of @ and # if the number 62684@# is divisible by both 8 and 5?

A. 4,0 B. 0,4 C. 4,4 D. 0,0 E. None

A. 4,0

aquarat_121

deepmind/aqua_rat

Speed of the train relative to man = 125/10 = 25/2 m/sec. = 25/2 * 18/5 = 45 km/hr Let the speed of the train be x km/hr. Then, relative speed = (x - 1) km/hr. x - 1 = 45 => x = 46 km/hr. Answer: E

A train 125 m long passes a man, running at 1 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?

A. 65 km/hr B. 17 km/hr C. 76 km/hr D. 50 km/hr E. 46 km/hr

E. 46 km/hr

aquarat_122

deepmind/aqua_rat

x ------- 8 (x + 10) ---- 6 x * 8 = (x + 10)6 x = 30 \Answer: B

A work which could be finished in 8 days was finished 3 days earlier after 10 more men joined. The number of men employed was?

A. 22 B. 30 C. 88 D. 71 E. 11

B. 30

aquarat_123

deepmind/aqua_rat

let the number be x, now x is halved => x/2..the question asks what is x? x(number) + x/2 (half of that number) = something => 3x/2 = something => x = 2 (something) / 3 so the answer choice must be divisible by 3 eliminate C, E right away check the rest B satisfies 3x/ 2 = 159 => x = 106 Verify. 106 + 53 = 159 Answer is B

Each digit in the two-digit number G is halved to form a new two-digit number H. Which of the following could be the sum of G and H

A. 153 B. 159 C. 137 D. 121 E. 89

B. 159

aquarat_124

deepmind/aqua_rat

Let the numbers 13a and 13b. Then, 13a x 13b = 2028 =>ab = 12. Now, the co-primes with product 12 are (1, 12) and (3, 4). [Note: Two integers a and b are said to be coprime or relatively prime if they have no common positive factor other than 1 or, equivalently, if their greatest common divisor is 1 ] So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4). Clearly, there are 2 such pairs. Answer: B

The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:

A. 9 B. 2 C. 7 D. 8 E. 1

B. 2

aquarat_125

deepmind/aqua_rat

Renuâ€™s one dayâ€™s work = 1/8 Sumaâ€™s one dayâ€™s work = 1/4 - 1/8 = 1/8 Suma can do it alone in 8 days. ANSWER:A

Renu can do a piece of work in 8 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone?

A. 8 B. 12 C. 14 D. 15 E. 17

A. 8

aquarat_126

deepmind/aqua_rat

Expl : Time taken to carry 2nd person = 300/50 = 6 hrs. Time taken to meet 3rd person =(300-6*10)/(50+10) = 4 hrs Time taken to carry 3rd person = 4 hours Time taken to meet 4th person = (300 –140)/60 = 8/3 Total time = 6+4+4+8/3+8/3 = 58/3 hours Answer :D

There are 4 people who has to cross a stretch of 300 km. They normally run at a speed of 10 kmph. One of them has a bike that travels at 50 kmph. The bike first takes one person alone and crosses the stretch while the other two keep running. Then he comes back without wasting time and picks up another person from the way, drives him across the stretch, and does the same for the last person. How long does this whole process take?

A. 24 hrs B. 16 hrs C. 56/3 hrs D. 58/3 hrs E. 18 hrs

D. 58/3 hrs

aquarat_127

deepmind/aqua_rat

X-X-X-X-X --> there are 5 odd digits from 1 to 9, inclusive thus options for the first and the last X's are: 5-X-X-X-X-4. Other X's can take following values: 5-7-6-5-4-4 -> 5*7*6*5*4*4=16800. Answer: E.

The security gate at a storage facility requires a Six-digit lock code. If the lock code must consist only of digits from 1 through 9, inclusive, with no repeated digits, and the first and last digits of the code must be odd, how many lock codes are possible?

A. 120 B. 240 C. 360 D. 720 E. 16800

E. 16800

aquarat_128

deepmind/aqua_rat

Sol. CP - = EC7 = 70 1-7 6 77-70 % Profit = 100 = 10% B

If by selling an article for Rs.60, a person loses 1/7 of money, what would he have gained or lost % by selling it for Rs.77?

A. 5% B. 10% C. 20% D. 30% E. 45%

B. 10%

aquarat_129

deepmind/aqua_rat

There are 60 minutes in an hour. In ¾ of an hour there are (60 * ¾) minutes = 45 minutes. In ¾ of an hour there are (60 * 45) seconds = 2700 seconds. Light flashed for every 6 seconds. In 2700 seconds 2700/6 = 450 times. The count start after the first flash, the light will flashes 451 times in ¾ of an hour. Answer:A

If a light flashes every 6 seconds, how many times will it flash in ¾ of an hour?

A. 451 times B. 638 times C. 838 times D. 436 times E. 435 times

A. 451 times

aquarat_130

deepmind/aqua_rat

Answer: CIt may be tempting to come up with a lot of variables, one each for each month's revenue for each company. However, focus on the differences. In the first month, the difference was +40 in favor of A. (Note that we can drop the thousands since every number in the question is in terms of thousands.) In the second, the difference was +6 in favor of A. The average was +2 in favor of A. With these numbers, use the average formula to find the third month (T): (40 + 6 + T)/3 = 2 46 + T = 6 T = -40 Since positive numbers indicate a difference in favor of A, negative numbers are in favor of B. -40 represents a $40,000 advantage in favor of Store B. Choice (B) is correct.

Revenues were recorded for Store A and Store B over a period of three months. In the first month, Store A's revenues were $40,000 higher than Store B's revenues. In the second month, Store A's revenues were $6,000 higher than Store B's revenues. If Store A's average (arithmetic mean) monthly revenue for the three months was $2,000 greater than Store B's average monthly revenue, then Store B's revenue in the third month was how much greater than Store A's revenue?

A. $14,000 B. $40,000 C. $42,000 D. $46,000 E. $50,000

B. $40,000

aquarat_131

deepmind/aqua_rat

( 6*6*5*4*3*2)/(2! *2!*2!)= 540 ways ANSWER:B

some digits were given like 0 2 2 3 3 4 4 then how many no will be there which is greater than 1 lac ,all numbers are distinct

A. 530 B. 540 C. 550 D. 560 E. 570

B. 540

aquarat_132

deepmind/aqua_rat

1 year = Rs. (854 - 815) = Rs. 39. 3 years = Rs.(39 x 3) = Rs. 117. Principal = Rs. (815 - 117) = Rs. 698 ANSWER B

A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is:

A. 600 B. 698 C. 675 D. 688 E. 900

B. 698

aquarat_133

deepmind/aqua_rat

If we put a= 1 then A. 2 B. 2 C. -4 E. -3 D. -3=-4 Not true

Each of the following equations has at least one solution EXCEPT D. Is it true?

A. -2*-a = 2a B. 2*a = (–2)*-a C. -4*a = -3-a D. -3*a = -3-a E. (–2)-a = –2-a

D. -3*a = -3-a

aquarat_134

deepmind/aqua_rat

Solution: Let average expenditure of 10 people be x. then, 10x = 20*5+5*(x+4); Or, 10x = 20*5+5x+20; Or, x = 24; So, total money spent = 24*10 = Rs. 240. Answer: Option D

10 people went to a hotel for combine dinner party 5 of them spent Rs. 20 each on their dinner and rest spent 4 more than the average expenditure of all the 10. What was the total money spent by them.

A. 1628.4 B. 1534 C. 1492 D. 240 E. None of these

D. 240

aquarat_135

deepmind/aqua_rat

It basically asks for the number of 5s in 150! 150/5 + 150/25 + 150/125 = 30 + 6 + 1. Hence 37 Answer: D.

If x is the product of the integers from 1 to 150, inclusive, and 5^y is a factor of x, what is the greatest possible value of y ?

A. 30 B. 34 C. 36 D. 37 E. 39

D. 37

aquarat_136

deepmind/aqua_rat

The final product is obtained by mixing 864 units of product M with water. In 864 units of Product M, amount of B = 864×77/108 = 616 In the final mixture, concentration of B is 50%. Therefore, the total quantity of final mixture = 616 × 2 = 1232 Water added = 1232 – 864 = 368 The correct answer is Choice B.

Product M is produced by mixing chemical X and chemical Y in the ratio of 5 : 4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1 : 3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2 : 1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M?

A. 328 units B. 368 units C. 392 units D. 616 units E. None of the above

B. 368 units

aquarat_137

deepmind/aqua_rat

Possible scenarios are: 1. Gold/Silver/Bronze/No medal (no ties) - 4!=24; 2. Gold/Gold/Silver/No medal - 4!/2!=12; 3. Gold/Silver/Silver/No medal - 4!/2!=12; 4. Gold/Gold/Gold/No medal - 4!/3!=4. Total Z: 24+12+12+4=52 Answer: B.

In a 4 person race, medals are awarded to the fastest 3 runners. The first-place runner receives a gold medal, the second-place runner receives a silver medal, and the third-place runner receives a bronze medal. In the event of a tie, the tied runners receive the same color medal. (For example, if there is a two-way tie for first-place, the top two runners receive gold medals, the next-fastest runner receives a silver medal, and no bronze medal is awarded). Assuming that exactly three medals are awarded, and that the three medal winners stand together with their medals to form a victory circle, how many Z different victory circles are possible?

A. 24 B. 52 C. 96 D. 144 E. 648

B. 52

aquarat_138

deepmind/aqua_rat

If X can complete a work in x days and Y can complete the same work in y days, then, both of them together can complete the work in x y/ x+ y days Therefore, here, the required number of days = 20Ã— 30/ 50 = 12 days. B)

X completes a work in 20 days and Y complete the same work in 30 days. If both of them work together, then the number of days required to complete the work will be?

A. 10 days. B. 12 days. C. 14 days. D. 8 days. E. 20 days.

B. 12 days.

aquarat_139

deepmind/aqua_rat

Formula = (Selling price ~ Cost price)/Cost price * 100 = (450- 300)/300= 40% gain B

A chair is bought for Rs.300/- and sold at Rs.420/- find gain or loss percentage

A. 15% loss B. 40% gain C. 25% gain D. 30% gain E. 35% gain

B. 40% gain

aquarat_140

deepmind/aqua_rat

The numbers less than 696 and are squares of certain numbers are 676, 625. The least number that should be subtracted from 696 to make it perfect square = 696 - 676 = 20. ANSWER:C

What is the least number to be subtracted from 696 to make it a perfect square?

A. 1 B. 16 C. 20 D. 71 E. 60

C. 20

aquarat_141

deepmind/aqua_rat

approach 1 at-least 1 paper back = total - no paper back 8c3-6c3 = 36 approach 2 at-least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back = 2c1*6c2+2c2*6c1 = 36 Answer is C

There are 8 books on a shelf, of which 2 are paperbacks and 6 are hardbacks. How many possible selections of 3 books from this shelf include at least one paperback?

A. a) 40 B. b) 45 C. c) 36 D. d) 55 E. e) 60

C. c) 36

aquarat_142

deepmind/aqua_rat

Explanation: Let sum = x then Simple Interest = x Rate = (100 * x) / (x * 20) = 5 Option D

If a sum of money doubles itself in 20 years at simple interest, the ratepercent per annum is

A. 12 B. 12.5 C. 13 D. 5 E. 14

D. 5

aquarat_143

deepmind/aqua_rat

Total cars=4 1.15*4=4.6->Service Cost Fuel Cost in Sports Car = 2*32*0.4=25.6 Fuel Cost in Executive Car=25.6*7/4=44.8 Total Fuel Cost = 25.6+44.8=70.4 Cost to fuel car = 70.4+4.6=75 Answer: B

In a fuel station the service costs $1.15 per car, every liter of fuel costs 0.4$. Assuming that you own 2 sports cars and 2 executive cars and all fuel tanks are empty. How much will it cost to fuel all cars together if a sports car tank is 32 liters and an executive car tank is 75% bigger?

A. 37.5$ B. 75$ C. 87.5$ D. 94.5$ E. 98.4$

B. 75$

aquarat_144

deepmind/aqua_rat

C EV The first letter moves one step forward. The second letter moves one step backward. Answer is C

Choose the missing terms out of the given alternatives. AZ, BY, CX, DW ?

A. EF B. GH C. EV D. DW E. KN

C. EV

aquarat_145

deepmind/aqua_rat

Total revenues = x Spent on marketing = x/4 Remaining amount = x-x/4 = 3x/4 1/7 of the remainder on maintenance of its facilities = 3x/4*1/7 = 3x/28 Amount left = 3x/4-3x/28 = 9x/14 Answer D

Company Z spent 1/4 of its revenues last year on marketing and 1/7 of the remainder on maintenance of its facilities. What fraction of last year’s original revenues did company Z have left after its marketing and maintenance expenditures?

A. 5/14 B. 1/2 C. 17/28 D. 9/14 E. 9/11

D. 9/14

aquarat_146

deepmind/aqua_rat

Speed = 45 * 5/18 = 25/2 m/sec Total distance covered = 360 + 140 = 500 m Required time = 500 * 2/25 = 40 sec ANSWER:A

A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

A. 40 sec B. 42 sec C. 45 sec D. 48 sec E. 58 sec

A. 40 sec

aquarat_147

deepmind/aqua_rat

For Maximum value : It should be less than 1/21 + 1/21 +1/21... 10 times = 10/21 ~ 1/2 For Minimum Value : It should be greater than 1/30+ 1/30+ 1/30 .. 10 times = 10/30 = 1/3 Thus, the answer should lie between 1/3 and 1/2. Correct ans : D.

What is the scope including 1/21+1/22+1/23+......+1/30?

A. 1/6~1/5 B. 1/5~1/4 C. 1/4~1/3 D. 1/3~1/2 E. 1/2~1

D. 1/3~1/2

aquarat_148

deepmind/aqua_rat

Looks easy: -- 9C4*5C1 + 9C5= 756 (E).

Company A has 13 employees, 9 of whom belong to the union. If 5 people work any one shift, and the union contract specifies that at least 4 union members work each shift, then how many different combinations of employees might work any given shift?

A. 56 B. 231 C. 336 D. 350 E. 756

E. 756

aquarat_149

deepmind/aqua_rat

Total number of balls = 5+2 = 7 n(S) = 7C3 = 7*6*5 / 3*2 = 35 n(E) = 2C2* 5C1 = 5 Probability = 5/35 = 1/7 Answer is A

A bag contains 5 red, 2 green balls. 3 balls are drawn randomly. What is the probability that balls drawn contain exactly two green balls?

A. 1/7 B. 2/9 C. 3/11 D. 4/17 E. 2/3

A. 1/7

aquarat_150

deepmind/aqua_rat

0.5x/21 + 0.5x/24 = 20 --> x/21 + x/24 = 40 --> x =448 km. D

A woman complete a journey in 20 hours. She travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km.

A. 334 km. B. 216 km. C. 314 km. D. 448 km. E. 544 km.

D. 448 km.

aquarat_151

deepmind/aqua_rat

Denote X as the sum of the heights of the two new people. From the stem it follows that (700+X)6>175. This reduces to X>350. Only the heights from B add up to 350 cm. All other pairs add up to more than 350 cm. Answer: B

The average height in a group of 4 people is 175 cm. If the average height increased when 2 more people were added to the group, which of the following cannot be the heights of the two new people?

A. 179 cm and 172 cm B. 181 cm and 169 cm C. 173 cm and 178 cm D. 176 cm and 176 cm E. 174 cm and 177 cm

B. 181 cm and 169 cm

aquarat_152

deepmind/aqua_rat

A+B=60 A=2B 2B+B=60===>B=20 A=40 5 yrs ages 45 and 25 Sum of their ages = 70 ANSWER A

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?

A. 70 B. 55 C. 60 D. 65 E. 80

A. 70

aquarat_153

deepmind/aqua_rat

Let the number be x. Then, 15x - x = 196 <=> 14x = 196 <=> x = 14. Answer :A

Find the number which when multiplied by 15 is increased by 196.

A. 14 B. 20 C. 26 D. 28 E. 30

A. 14

aquarat_154

deepmind/aqua_rat

Average of 5, 7, 14 and Y = ( 5 + 7 + 14 + Y )/ 4 Therefore, X = 80% of ( 5 + 7 + 14 + y )/ 4 = (80/100) x (26 + Y)/4 => X = (26 + Y)/5 5X - Y = 26----- (i) Also, (X + Y)/2 = 26 ----- (ii) From (i)and (ii) X = 13 Y = 39. ANSWER:C

A number X equals 80% of the average of 5, 7, 14 and a number Y. If the average of X and Y is 26, the value of Y is?

A. 13 B. 26 C. 39 D. 36 E. None of these

C. 39

aquarat_155

deepmind/aqua_rat

Let distance = x m Usual rate = y kmph x/y – x/y+3 = 40/60 hr 2y(y+3) = 9x ---------------------------------(1) x/y-2 – x/y = 40/60 hr y(y-2) = 3x -----------(2) divide 1 & 2 equations by solving we get x = 40 km Answer : B

A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is.

A. 30 km B. 40 km C. 45 km D. 50 km E. 55 km

B. 40 km

aquarat_156

deepmind/aqua_rat

Number plugging in will be best strategy for this question. Let p = 5%, Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence D is the correct answer.

The number of livestock in a farm at the beginning of year 2000 was 130,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 130,000. Which of the following expressions is correct?

A. With the exception of 1 instance, p will be equal to q B. q > p C. p = q D. p > q E. There is no relation between p and q

D. p > q

aquarat_157

deepmind/aqua_rat

Explanation: 3 men reap 1/10 field in 1 day 1 man reap 1/(3 x 10) 4 women reap 1/10 field in 1 day 1 woman reap 1/(10 x 4) 5 men and 6 women reap (5/(3 x 10)+ 6/(4 x 10)) =19/60 in 1 day 5 men and 6 women will reap the field in 19/60 days Answer: Option A

If 3 men or 4 women can reap a field in 10 days how long will 5 men and 6 women take to reap it?

A. 19/60 B. 9/60 C. 2/3 D. 5/18 E. 6/24

A. 19/60

aquarat_158

deepmind/aqua_rat

15^n = 5^n * 3^n Highest prime factor will be the limiting factor. 100/5 +100/25 =20+4 = 24 ANSWER:E

What is the greatest possible value of integer n if 100! is divisible by 15^n

A. 20 B. 21 C. 22 D. 23 E. 24

E. 24

aquarat_159

deepmind/aqua_rat

2nd term = (1st term) * 1 + 1 = 15 *1 + 1 = 16. 3rd term = (2nd term) * 2 + 2 = 16 * 2 + 2 = 34 4th term = (3th term) *3 + 3 = 34 * 3 + 3 = 105 5th term = (4th term) * 4 + 4 = 105 * 4 + 4 = 424 6th term = (5th term) * 5 + 5 = 424 * 5 + 5 = 2125 6th term should 2125 instead of 2124. E

Find the invalid no.from the following series 15, 16, 34, 105, 424, 2124, 12756

A. 15 B. 16 C. 34 D. 105 E. 2124

E. 2124

aquarat_160

deepmind/aqua_rat

To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/4 > 1/5. The greatest multiple of 4 less than 45 is 40 (such that the remaining number is divisible by 5), so let's assume there were 40 dogs and 5 cats. Then the maximum number of adopted pets is 1/4*(40) + 1/5*(5) = 10 + 1 = 11. The answer is B.

On Monday, a certain animal shelter housed 45 cats and dogs. By Friday, 1/5 of the cats and 1/4 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?

A. 10 B. 11 C. 12 D. 13 E. 14

B. 11

aquarat_161

deepmind/aqua_rat

Original price = 1120 × 100⁄70 × 100⁄80 = 2000 Answer D

A shopkeeper gave an additional 20 per cent concession on the reduced price after giving 30 per cent standard concession on an article. If Arun bought that article for 1,120, what was the original price?

A. 3,000 B. 4,000 C. 2,400 D. 2,000 E. None of these

D. 2,000

aquarat_162

deepmind/aqua_rat

(A+B)-(B-C)=10 A-C=10 Answer is C

The total age of A and B is 10 years more than the total age of B and C. C is how many years younger than A.?

A. 16 B. 12 C. 10 D. 20 E. 10

C. 10

aquarat_163

deepmind/aqua_rat

100 % - 10 % = 90 % 54%-36%=18% 18% ------> 3600 ( 18 × 200 = 3600) 100% -------> 20000 votes (100 × 200 = 20000) C

In an election between two candidates, 10% of votes are were declares invalid. First candidate got 3600 votes which were 60% of the total valid votes . The total number of votes enrolled in that election was:

A. 9000 B. 98000 C. 20000 D. 11000 E. 12000

C. 20000

aquarat_164

deepmind/aqua_rat

A The number is: 12345679 12345679 * 9 = 111111111 12345679 * 18 = 222222222 12345679 * 27 = 333333333 And so on...

Find a 8 digit number that if multiplied by the number 9 or any of its multiplications products (18, 27, 36, 45,..) will result in the multiplication factor repeated (n) number of times.

A. 12345679 B. 42345675 C. 22347379 D. 52345673 E. 21345679

A. 12345679

aquarat_165

deepmind/aqua_rat

(3*6 + 6*6): (7*12) 54:84 => 9:14.Answer:C

A and B invests Rs.3000 and Rs.7000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?

A. 9:6 B. 9:8 C. 9:14 D. 9:9 E. 9:5

C. 9:14

aquarat_166

deepmind/aqua_rat

Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80*(20/100) = Rs. 96 Present Savings = 100 – 96 =Rs. 4 100 ------ 4 ? --------- 200 => 5000 Answer: A

A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 20%, he is only able to save Rs. 200 per month. What is his monthly salary?

A. 5000 B. 2889 C. 2779 D. 6257 E. 5362

A. 5000

aquarat_167

deepmind/aqua_rat

Let the speed of the water in still water =x Given that speed of the stream = 3 kmph Speed downstream =(x+3) kmph Speed upstream =(xâˆ’3) kmph He travels a certain distance downstream in 1 hour and come back in 11â„2 hour. i.e., distance travelled downstream in 1 hour = distance travelled upstream in 11â„2 hour Since distance = speed Ã— time, we have (x+3)Ã—1=(x-3)3/2 2(x+3)=3(x-3) 2x+6=3x-9 x=6+9=15 kmph Answer: D

A boat covers a certain distance downstream in 1 hour, while it comes back in 11â„2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?

A. 31 kmph B. 16 kmph C. 19 kmph D. 15 kmph E. 14 kmph

D. 15 kmph

aquarat_168

deepmind/aqua_rat

A : B (4000*4)+(1000*8) : (6000*8)+(3000*4) 24000 : 60000 2 : 5 Answer: A

A and B invests Rs.4000 and Rs.6000 in a business. After 4 months, A withdraws three-fourth of his capital and 4 months later, B withdraws half of his capital. In what ratio should they share the profits at the end of the year?

A. 2:5 B. 3:5 C. 4:5 D. 3:7 E. 5:7

A. 2:5

aquarat_169

deepmind/aqua_rat

The pattern is + 0.05, + 0.10, + 0.15, ..... Answer : D.

0.5, 0.55, 0.65, 0.8, ?

A. 0.7 B. 0.9 C. 0.95 D. 1 E. 2

D. 1

aquarat_170

deepmind/aqua_rat

15 W = 10 M Now, 5W + 4M = 5W + 4×15/10W = 5W + 6W = = 11 W If 15 women can complete the project in 55 days, 11 women can complete the same project in 55×15/11=75days Answer A

If 15 women or 10 men can complete a project in 55 days, in how many days will 5 women and 4 men working together complete the same project ?

A. 75 B. 8 C. 9 D. 85 E. None of these

A. 75

aquarat_171

deepmind/aqua_rat

450 = 2 * 3^2 * 5^2 If 450 divides n^2, then n must be divisible by 2 * 3 * 5 = 30 The answer is C.

If n is a positive integer and n^2 is divisible by 450, then what is the largest positive integer that must divide n?

A. 10 B. 20 C. 30 D. 40 E. 50

C. 30

aquarat_172

deepmind/aqua_rat

1/10 + 1/15 = 1/6 * 4 = 2/3 1 - 2/3 = 1/3 1/10 + 1/15 - 1/x = 1/3 x = 8 Answer:B

Two pipes A and B can separately fill a cistern in 10 and 15 minutes respectively. A person opens both the pipes together when the cistern should have been was full he finds the waste pipe open. He then closes the waste pipe and in another 4 minutes the cistern was full. In what time can the waste pipe empty the cistern when fill?

A. 6 B. 8 C. 7 D. 4 E. 1

B. 8

aquarat_173

deepmind/aqua_rat

Each member out of 14, including Harry, has equal chances to be selected for any of the positions (the sequence of the selection is given just to confuse us). The probability that Harry will be selected to be the secretary is 1/14 and the probability that Harry will be selected to be the treasurer is also 1/14. So, the probability that Harry will be selected to be either the secretary or the the treasurer is 1/14+1/14=2/14. Answer: D.

A certain club has 14 members, including Harry. One of the 14 members is to be chosen at random to be the president, one of the remaining 13 members is to be chosen at random to be the secretary, and one of the remaining 12 members is to be chosen at random to be the treasurer. What is the probability that Harry will either be the secretary or the member chosen to be the treasurer?

A. 5/7 B. 4/7 C. 3/7 D. 1/7 E. 2/7

D. 1/7

aquarat_174

deepmind/aqua_rat

Explanation: From given details we know that she walks in square shaped path and will be in 1 km away from starting point. ANSWER IS C

Afreena walks 8 km towards East and then walks 13 km back, then she turns left and walks 4 km; then walks 5 km after turning left; she turns left again and walks 3 km. How far is she from the starting point ?

A. 3 km B. 2 km C. 1 km D. 6 km E. 7 km

C. 1 km

aquarat_175

deepmind/aqua_rat

W women and M men..now 4 women and 2 men are added then total women = W+4 and total men = M+2.. if we club both as total one team (W + M + 6) We need to find the probability that the team captain will be a woman => W+4 / (W + M + 6).. IMO option A is correct answer...

A coed soccer team has W women and M men on the team. If 4 women and 2 men are added to the team roster, and if one person on the team is selected at random to serve as team captain, then the probability that the team captain will be a woman can be represented as

A. (W + 4)/(W + M + 6) B. (W + 4)/(W + M + 2) C. (W + 4)/(M + 2) D. (W + 4)/(W + M) E. W/M

A. (W + 4)/(W + M + 6)

aquarat_176

deepmind/aqua_rat

Solution Let the son's present age be x years .Then, man's present age = (x+30)years. Then â€¹=â€º(x+30)+2= 2(x+2) â€¹=â€ºx+32=2x+4 x= 28. Answer B

A man is 30 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is

A. 14 years B. 28 years C. 20 years D. 22 years E. None

B. 28 years

aquarat_177

deepmind/aqua_rat

1 lbs of raisin = $1 3 lbs of raisin = $3 1 lbs of nuts = $3 3 lbs of nuts = $9 Total value of mixture = 9+3 = 12 Fraction of the value of raisin = 3/12 = 1/4 Ans:C

Chris mixed 3 pounds of raisins with 3 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?

A. 1/7 B. 1/5 C. 1/4 D. 1/3 E. 3/7

C. 1/4

aquarat_178

deepmind/aqua_rat

2^(2w) = 8^(w−2) 2^(2w) = 2^(3*(w−2)) 2^(2w) = 2^(3w-6) Let's equate the exponents as the bases are equal. 2w = 3w-6 w = 6 The answer is B.

If 2^(2w) = 8^(w−2), what is the value of w?

A. 3 B. 6 C. 9 D. 12 E. 15

B. 6

aquarat_179

deepmind/aqua_rat

Solution Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours. =170 hours. The watch gains = (2 + 4 x4/5)min = 34 / 5 min.in 170 hrs. Now,34/5 min are gained in 170 hrs. 2 min are gained in(170x 5/34 x2)hrs. Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m.on Wednesday. Answer B

A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?

A. 2 p.m. on Tuesday B. 2 p.m. on Wednesday C. 3 p.m. on Thursday D. 1 p.m. on Friday E. None

B. 2 p.m. on Wednesday

aquarat_180

deepmind/aqua_rat

Let's say the two cars have speeds V1 and V2. The fact that they are moving in opposite direction means that their relative speed is (V1 + V2). In other words, any gap between them will be changing in size at a rate of (V1 + V2). It doesn't matter whether they are moving toward each other or away from each other. If they are approaching each other, the gap between them is decreasing at a rate of (V1 + V2). If they are moving away from each other, the gap between them is increasing at a rate of (V1 + V2). Either way, the number for the rate of change remains the same. Here, the two cars approach a distance 40 mi, then move away from each other another distance of 40 miles. That's a total distance of 80 miles in 1.5 hr, which gives a rate of: R = (80 mi)/(1.5) = 53.33 mph That's the rate of change of the gap, so it must equal the sum of the speeds of the two cars. One of the speeds is x, and let's call the other y. We want y. x + y = 53.33 y = 53.33 - x Answer =(B)

Otto and Han are driving at constant speeds in opposite directions on a straight highway. At a certain time they are driving toward each other and are 40 miles apart. One and a half hours later, they are again 40 miles apart, driving away from each other. If Otto drives at a speed of x miles per hour, then, in terms of x, Han drives at a speed of how many miles per hour?

A. a) 80-x B. b) 53.33-x C. c) 80-2x D. d) 120-x E. e) 40-x/2

B. b) 53.33-x

aquarat_181

deepmind/aqua_rat

theta degree=11/2m-30h =11/2(45)-30(3) =247.5-90 =157.5 or 157 1/2 degree ANSWER:E

The angle between two hands at 3.45 is

A. 110 degree B. 115 degree C. 112 1/2 degree D. 117 degree E. 157 1/2 degree

E. 157 1/2 degree

aquarat_182

deepmind/aqua_rat

Time = 4 Distance = 620 3/2 of 4 hours = 4 * 3/2 = 6 Hours Required speed = 620/6 = 103 Kmph D)

A jeep takes 4 hours to cover a distance of 620 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?

A. 148 Kmph B. 152 Kmph C. 106 Kmph D. 103 Kmph E. 165 Kmph

D. 103 Kmph

aquarat_183

deepmind/aqua_rat

Solution At 8 o'clock, the hour is at 8 and the minute hand is at 12,i.e. the two hands are 20 min. Spaces apart. So, the minute hand gain = (30 - 20)minute 55 minutes will be gained in 60 min. 10 minutes spaces will be gained in (60/55 x10) min. = 10x10/11 min. The hands will be in the same straight line but not together at 10x10/11 min.past 8. Answer B

Find at what time between 8 and 9 o'clock will the hands of a clock be in the same straight line but not together.

A. 10x11/10 B. 10x10/11 C. 11x10/11 D. 12x10/11 E. None

B. 10x10/11

aquarat_184

deepmind/aqua_rat

If Pugsley were to give Wednesday four of his spiders, Wednesday would then have five times as many spiders as Pugsley does: (w + 4) = 4(p - 4) If Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded: p + 5 = w - 5 Solving gives p = 10 and w = 20. Answer: D.

On Sunday morning, Pugsley and Wednesday are trading pet spiders. If Pugsley were to give Wednesday four of his spiders, Wednesday would then have four times as many spiders as Pugsley does. But, if Wednesday were to give Pugsley five of her spiders, Pugsley would now have five fewer spiders than Wednesday had before they traded. How many pet spiders does Pugsley have before the trading game commences?

A. 6 B. 7 C. 8 D. 10 E. 12

D. 10

aquarat_185

deepmind/aqua_rat

6C2 + 6C3 = 15 + 20 = 35 The answer is B.

To apply for the position of photographer at a local magazine, a photographer needs to include two or three photos in an envelope accompanying the application. If the photographer has pre-selected six photos representative of her work, how many choices does she have to provide the photos for the magazine?

A. 32 B. 35 C. 36 D. 40 E. 42

B. 35

aquarat_186

deepmind/aqua_rat

Just to add some more to Bunuel's explanation, if a number is a multiple of 3, it will be in a form: n = 3*k, where k is an integer And if a number is a multiple of 6, it will be in a form : m = 6*l, where l is an integer so m = 2 * 3 * l = (2*l) * 3 = 3 * p, where p is an integer. In other words, the prime factorization of m must have 3 as a factor, if it's a multiple of 6, but the expression can't have that (as explained by Bunuel), so it can't be a multiple of 6 either ANSWER:C

If x is an integer and y = 3x + 2, which of the following CANNOT be a divisor of y?

A. 4 B. 5 C. 6 D. 7 E. 8

C. 6

aquarat_187

deepmind/aqua_rat

C.P. = 400W S.P. = 1.8W*150 + 1.2W*100 + 0.6W*150 = 480W Since, S.P. > C.P., there is net profit. Profit = S.P. - C.P. = 480W - 400W = 80W Profit % = (Profit/C.P.)*100 = (80W/400W)*100 = 20% So, the correct answer is D.

A book store bought copies of a new book by a popular author, in anticipation of robust sales. The store bought 400 copies from their supplier, each copy at wholesale price W. The store sold the first 150 copies in the first week at 80% more than W, and then over the next month, sold a 100 more at 20% more than W. Finally, to clear shelf space, the store sold the remaining copies to a bargain retailer at 40% less than W. What was the bookstore’s net percent profit or loss on the entire lot of 400 books?

A. 30% loss B. 10% loss C. 10% profit D. 20% profit E. 60% profit

D. 20% profit

aquarat_188

deepmind/aqua_rat

Total no of ways in which you can select a committee of 2 people out of 7 people is 7C2 ways= 21 ways Requirement is at-least 1 preacher= 4C1*3C1+4C2 or 7C2-3C2=18 ways Probability= 18/21 = 6/7 ANSWER:D

A committee of 2 people is to be selected out of 3 teachers and 4 preachers. If the committee is selected at random, what is the probability that the committee will be composed of at least 1 preacher?

A. 1/4 B. 1/3 C. 2/3 D. 6/7 E. 8/9

D. 6/7

aquarat_189

deepmind/aqua_rat

Prime Factoring: you need a 2 and a 5 to make a 10 (a "zero"), and there are TONS of 2's so let's skip these and focus on the (rarer) 5s: 80! = 1*2*3*4*5*6...*78*79*80 Since there are 80 consecutive numbers, there are 16 multiples of 5 in there, but if we're prime factoring, we need to remember that SOME multiples of 5 actually contain more than just one 5. Which? 25 comes to mind -- it's got two of them! So all the multiples of 25 actually contain two 5's (ie: 50 and 75) So, to recap, we have 16 of them, plus 3 more (the additional 5's in 25, 50, and 75), so that makes 19, and since we have more than enough 2's, we know our number will have exactly 19 zeros at the end. ANSWER:D

If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end?

A. 16 B. 17 C. 18 D. 19 E. 20

D. 19

aquarat_190

deepmind/aqua_rat

Juan's income = 100 (assume); Tim's income = 60 (40 percent less than Juan's income); Mary's income = 96 (60 percent more than Tim's income). Thus, Mary's income (96) is 96% of Juan's income (100). Answer: C

Mary's income is 60 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?

A. 124% B. 120% C. 96% D. 80% E. 64%

C. 96%

aquarat_191

deepmind/aqua_rat

They should share the profits in the ratio of their investments. The ratio of the investments made by Y and Z = 3000 : 6000 => 1:2 . Answer:E

Y and Z start a business with Rs.3000 and Rs.6000 respectively. How should they share their profits at the end of one year?

A. 4:1 B. 1:3 C. 1:4 D. 1:5 E. 1:2

E. 1:2

aquarat_192

deepmind/aqua_rat

he answer will be a number which doesn't completely divide 100! No of 5's in 100! = 24 No of 7's in 100! = 16 No of 11's in 100! = 9 No of 13's in 100! = 7 No of 17's in 100! = 5 There are 5 seventeens in 100! , however we are dividing by 17^6 , so this can not divide 100! Hence our answer will be E

If 100!/x is not an integer, which of the following could be the value of x?

A. 5^24 B. 7^16 C. 11^9 D. 13^6 E. 17^6

E. 17^6

aquarat_193

deepmind/aqua_rat

Let age of R =x. Then, Age of Q =2x Age of P =2+2x Total age of P,Q and R =25 ⇒(2+2x)+2x+x=25 ⇒5x=23 ⇒x=23/5=4.6 years B's age =2x=2×4.6=9.2 years ANSWER:D

P is two years older than Q who is twice as old as R. The total of the ages of P, Q and R is 25. How old is Q?

A. 7.2 years B. 8.2 years C. 9.8 years D. 9.2 years E. 9.4 years

D. 9.2 years

aquarat_194

deepmind/aqua_rat

M = 20 S = 7 DS = 20 + 7 = 27 Answer: D

A man can row with a speed of 20 kmph in still water. If the stream flows at 7 kmph, then the speed in downstream is?

A. 27 B. 23 C. 20 D. 27 E. 12

D. 27

aquarat_195

deepmind/aqua_rat

Deviation from the mean for the daytime staff = 75 - 65 = 10. Deviation from the mean for the evening staff = 65 - 60 = 5. Thus, the ratio of the number of daytime staff members to the number of evening staff members is 5:10 = 1:2. The answer is A.

A theater box office sold an average (arithmetic mean) of 65 tickets per staff member to a particular movie. Among the daytime staff, the average number sold per member was 75, and among the evening staff, the average number sold was 60. If there are no other employees, what was the ratio of the number of daytime staff members to the number of evening staff members?

A. 1:2 B. 1:4 C. 5:11 D. 1:3 E. 13:15

A. 1:2

aquarat_196

deepmind/aqua_rat

Let the present ages of Sameer and Anand be 5x years and 4x years respectively. Then, (5x + 4/4x + 4)=11/9 9(5x + 4) = 11(4x + 4) 45x + 36 = 44x + 44 45x - 44x = 44 - 36 x = 8. Anand's present age = 4x = 32 years. Answer:D

Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Four years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?

A. A)24 B. B)89 C. C)67 D. D)32 E. E)45

D. D)32

aquarat_197

deepmind/aqua_rat

18 m/s = 12 * 18/5 kmph 3 hours 45 minutes = 3 3/4 hours = 15/4 hours Distance = speed * time = 18 * 18/5 * 15/4 km = 243 km. Answer: E

If a man can cover 18 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?

A. 288 B. 162 C. 878 D. 168 E. 243

E. 243

aquarat_198

deepmind/aqua_rat

Explanation: Meaningful words are ROSE, SORE and EROS. Note the meaning of the words SORE and EROS with the help of dictionary. Answer: B) Three

How many meaningful English words can be formed with the letters ESRO using each letter only once in each word?

A. 1 B. 3 C. 4 D. 8 E. 9

B. 3

aquarat_199

deepmind/aqua_rat